How strong would a magnetic field need to be in order to make a particle with a mass of 4*10^-11 kg and a charge of 8nC move in a circular path with a speed of 400ms and a radius of 0.5 m?
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A: The ratio is given by 9.84*104 C/kgExplanation:
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A: Given Data Uniform magnetic field is given as B→=(30.0 i^-20.0j^) mT=(30.0i^-20.0j^ )×10-3 T…
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A: Given, mass of the proton, mp = 1.67×10-27 kg charge of the proton, qp = 1.60 ×10-19 C speed of the…
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A: (a) Here the potential difference is V=4000V Then the electric field will be E=Vd=40000.1=40000V/m…
Q: A uniform magnetic field of magnitude 0.20Tis directed along the positive x axis. A positron moving…
A: Given that,B=0.2Tv=1×107 m/sAngle with field is 80°mp=9.11×10-31 kgq=1.6×10-19 CWe know that,Pitch…
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Q: A nucleus with 44 protons travels at a velocity of 2.05 x 10^6 m/s through a region of uniform…
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Q: Q4 :proton move in circular path with radius 14 cm inside the magnetic field B= 0.35 T perpendicular…
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Q: hat is the radius of a proton's trajectory when it moves at 2.4x106 m/s perpendicular to a magnetic…
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Q: In 1932, Ernest Lawrence invented the cyclotron, in which a strong vertical magnetic field acted on…
A: In 1932, Ernest Lawrence invented the cyclotron, in which a strong vertical magnetic field acted on…
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A: Given, Magnetic field=8.60T
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A: Formula:f=qB2πmRe-arranging the above equation we get, m=qB2πf-----(1)where, q=1.6×10-19 Cf=2.3×106…
Q: be produced with a maximum speed of 4.8×107 m/s? Give answer to 2 decimals.
A: Given B = 0.77 T maximum speed vmax = 4.8×107 m/s charge on proton q = 1.6×10-19 C mass of…
Q: What is the magnetic force on a particle that has 0.000500 C of charge and is moving at 2.50 × 105…
A: Answer:- Given Charge (q) = 0.000500 C Velocity (V) = 2.50 × 105 m/s Magnetic field (B) = 4.20 T…
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Q: (unrealistic) E/M Forces 6. A particle of charge q = 0.25C and mass m = 1.0kg is moving with a…
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Q: A próton with a net positive charge of 1.6e-19 Coulombs and a mass of 1.67e- 27 kg takes 3 days to…
A: Given a proton with m=1.67×10-27kgq= 1.6×10-19C earths magnetic field B=.5×10-4T
Q: A proton (with charge of 1.6 x 10^-19 C and mass of 1.7*10^-27 kg) traveling at a speed of…
A: Given Charge on proton q=1.6×10-19 C Mass of proton m=1.7×10-27 kg Speed of proton v=53045750 m/s…
Q: A carbon-14 ion with a charge of +6.408x10^-19 C and a mass of 2.34x10^-26 kg is sent through a mass…
A: Given, Charge of the ion q=6.408×10-19 C mass m=2.34×10-26kg Magnetic field strength B=0.500T…
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Q: A carbon-14 ion with a charge of +6.408x10^-19 C and a mass of 2.34x10^-26 kg is sent through a mass…
A: For circular motion the velocity is v=qBrm Here q is charge, B is magnetic field, r is the radius of…
Q: An electron (q = 1.6 x 10^-19 C, m = 9.11 x 10^-31 kg) enters a cyclotron with an unknown magnetic…
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- 16. A particle with a charge of 0.06 C is moving atright angles to a uniform magnetic field with astrength of 0.5 T. The velocity of the charge is 600m/s. What is the magnitude of the magnetic forceexerted on the particle?What is the force acting on a 1.6(10)–19 C charge when it is moving at 3(10)7m/s perpendicular to a magnetic field whose strength is 0.02 T? What is the radius of the particle’s trajectory if the mass of the particle is 3.3(10)-27 kg?A proton travels through a 0.75 T magnetic field in a circle with a radius of 0.30 m. What is the momentum of this proton?
- An object with a charge of +0.3 C moves through a magnetic field of strength 40 T with a velocity of 200m/s as shown. How much force does the magnetic field apply on the particle?A pellet which holds a charge of 10 coulombs is moving upwards (+Y) and driven by an electric field in the same direction with a magnitude of 50 V/m. There is a magnetic field with a magnitude of 25 Tesla’s pointing downwards (-Y). How fast does the pellet need to be going for the magnetic force to cancel the electric force? Group of answer choices 0.5 m/s 2 m/s 4 m/s The forces will cancel out at any speed the pellet may be travelling In this case, the electric force cannot be canceled out by the magnetic forceQ. 3: A proton moves through a uniform magnetic field given by B = (30 î – 205) mT. At a time t1, the proton has a velocity given by = the proton is FB (Vz î + (2000m/s)ĵ) and the magnetic force of (4 * 10-17N) k. At that instant, what is the velocity vx?
- A proton is moving under the combined influence of an electric field (E = 2569 V/m) and a magnetic field (B = 2.45 T), as shown in the figure. Assuming the proton is moving in the direction shown in the figure with speed 255 m/s at the instant it enters the crossed fields, what is the acceleration of the proton? (units are in m/s^2)If an electron that’s entering a magnetic field B=2.0 with a velocity of V =2.0x10^7 m/s parallel to B experiences a magnetic force F b= ????A 3.5 mC charge moves with a speed of 10,000 m/s in a magnetic field of 0.5 T. How much force is exerted on the charge?