MN.14. How much stomach acid was neutralized by the 4.3628 g tablet?Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer.abсd59.1 mL88.6 mL73.9 mL118.2 mLA student is given an antacid tablet that weighs 5.6832 g. The tablet was crushed and 4.3628 g of theantacid was added to 200 mL of simulated stomach acid. This was allowed to react and then filtered.It was found that 25.00 mL of this partially neutralized stomach acid required 11.25 mL of a NaOHsolution to titrate it to a methyl red end point.It took 27.5 mL of this NaOH solution to neutralize 25.00 mL of the original stomach acid.

(i) First, find the mL of NaOH needed for each mL of stomach acid by using the data given for the…

How much stomach acid was neutralized by the 4.3628 g tablet? Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a b с d 59.1 mL 88.6 mL 73.9 mL 118.2 mL

How much stomach acid was neutralized by the 4.3628 g tablet? Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a b с d 59.1 mL 88.6 mL 73.9 mL 118.2 mL

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

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MN.14.

How much stomach acid was neutralized by the 4.3628 g tablet?
Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer.
a
b
с
d
59.1 mL
88.6 mL
73.9 mL
118.2 mL
A student is given an antacid tablet that weighs 5.6832 g. The tablet was crushed and 4.3628 g of the
antacid was added to 200 mL of simulated stomach acid. This was allowed to react and then filtered.
It was found that 25.00 mL of this partially neutralized stomach acid required 11.25 mL of a NaOH
solution to titrate it to a methyl red end point.
It took 27.5 mL of this NaOH solution to neutralize 25.00 mL of the original stomach acid.

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