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How much ice is required to reduce the temperature of the following fresh concrete to 16°C. If the w/c ratio is to remain same, find also the amount of water to be added to the concrete. (Neglect the aggregate moisture) Mix proportion = 1:1.8:4.5, w/c ratio= 0.6, cement content = 300 kg/m³ Temp. of cement =18 °C, temp, of water- 20 °C, temp. of aggregate= 30 °C. L=ratio of latent heat of fusion of ice to the specific heat of water= 80 °C. T = 0.22(TaWa+ TcWc) + TwWw+TwaWwa-80Wi 0.22 (Wa+Wc) + Ww + Wwa + Wi

How much ice is required to reduce the temperature of the following fresh concrete to 16°C. If the w/c ratio is to remain same, find also the amount of water to be added to the concrete. (Neglect the aggregate moisture) Mix proportion = 1:1.8:4.5, w/c ratio= 0.6, cement content = 300 kg/m³ Temp. of cement =18 °C, temp, of water- 20 °C, temp. of aggregate= 30 °C. L=ratio of latent heat of fusion of ice to the specific heat of water= 80 °C. T = 0.22(TaWa+ TcWc) + TwWw+TwaWwa-80Wi 0.22 (Wa+Wc) + Ww + Wwa + Wi

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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How much ice is required to reduce the temperature of the following fresh concrete to 16°C. If the w/c ratio is to remain same, find also the amount of water to be added to the concrete. (Neglect the aggregate moisture) Mix proportion = 1:1.8:4.5, w/c ratio= 0.6, cement content = 300 kg/m³ Temp. of cement =18 °C, temp, of water-= 20 °C, temp. of aggregate= 30 °C. L=ratio of latent heat of fusion of ice to the specific heat of water= 80 °C. T = 0.22(TaWa + TcWc) + TwWw+TwaWwa - 80W₁ 0.22(Wa+Wc) + Ww + Wwa + Wi
Transcribed Image Text:How much ice is required to reduce the temperature of the following fresh concrete to 16°C. If the w/c ratio is to remain same, find also the amount of water to be added to the concrete. (Neglect the aggregate moisture) Mix proportion = 1:1.8:4.5, w/c ratio= 0.6, cement content = 300 kg/m³ Temp. of cement =18 °C, temp, of water-= 20 °C, temp. of aggregate= 30 °C. L=ratio of latent heat of fusion of ice to the specific heat of water= 80 °C. T = 0.22(TaWa + TcWc) + TwWw+TwaWwa - 80W₁ 0.22(Wa+Wc) + Ww + Wwa + Wi
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