How much heat is required to raise the temperature of 250 mL of water from 20 o C to 35 o C ? How much heat is lost by the water as it cools back down to 20 o C
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How much heat is required to raise the temperature of 250 mL of water from 20 o C to 35 o C ?
How much heat is lost by the water as it cools back down to 20 o C
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- What quantity of joules of energy are needed to transform 11 kg of ice at 0.00°C to vapor at 155°C? Specific heat of water is cwater = 4186 J/kg C° Specific heat of steam is csteam = 2010 J/kg C° Latent heat of fusion of water is Lfusion = 3.33 X 105 J/kg Latent heat of vaporization of water is Lvaporization = 2.26 X 106 J/kg Boiling point of water = 100° CA 85 g iron bar (specific heat =450J/kg C) at 100 °C is placed into 230 g of water at 15 "C. What will be the final temperature of the iron bar as it cools in the water? Your Answer: AnswerIce at 0 degree C with a mass of 200 g is tossed into a pot of boiling water. The boiling water is at 100 degree C and has a mass of 1 kg. What is the final temperature of the water after the ice melts? (Lf = 3.33 x 10^5 J/kg, Cwater 4186 J/kg degreeC)
- A 450 mL cup of coffee is too hot to drink at 91C, so 100.0 mL of cold water at 6.5 C is added to cool it off. What is the final temperature of the drink?A 96g iron bar at 100°C is placed in water so that it looses 350 J of heat. If the specific heat capacity of iron is 0.450 J/gºC, to what final temperature will the iron bar cool? BIVIA new liquid substance has been discovered that freezes at -23°C. A scientist poured the liquid (which was at -23°C) Into a 0.6 kg cup (Coup = 793 J/kg-K) which caused some, but not all, of the liquid to freeze (only 0.216 kg of the liquid froze). As a result, the liquid lost 40,000 J of heat until thermal equilibrium was reached. Determine the latent heat of the substance & the Initial temperature of the cup. Topul °℃
- Calculate the amount of heat needed to change the temperature of 2 kg of steam from 110 0C to -4 0 Use the following in working this question: Specific heat of water = 1 kcal/kg.0c Specific heat of ice = 0.5 kcal/kg.0c Specific heat of steam = 0.5 kcal/kg.0c Latent heat of fusion = 80 kcal/kg Latent heat of vaporization = 540 kcal/kgWhat is the ratio of the energy required to warm 125 g of Ice (0.0 \deg C) to body temperature (37 \deg C) to warming the same amount of water through the same temperature change? Answer format is the number Eice/Ewater = (2 significant figures) Latent Heat of Fusion of Water: 335, 000 J/kg Specific Heat Capacity of Water: 4186 J/kg/\deg C