How much heat is required to change 472 g of ice at -11°C to steam at 106°C? cice = 2090 J/kg C c water = 4184 J/kg C c steam = 2020 J/kg C Lf = 335,000 J/kg Lv = 2,256,000 J/kg Find the heat necessary to turn 8 kg of ice at -8 into water at 11. c Ice = 2090 J/(kg oC) c Water = 4187 J/(kg oC) c Steam = 1996 J/(kg oC) Lf = 335,000 J/kg Lv = 2,260,000 J/kg In order to change some amount of ice at 0 deg C into steam at 110 deg C, there are four steps: • melt the ice into water • heat the water that used to be ice • boil the water into steam • heat the steam Which step requires the most heat? c Ice = 2090 J/(kg oC) c Water = 4187 J/(kg oC) c Steam = 1996 J/(kg oC) Lf = 335,000 J/kg Lv = 2,260,000 J/kg A) melt the ice into water
How much heat is required to change 472 g of ice at -11°C to steam at 106°C? cice = 2090 J/kg C c water = 4184 J/kg C c steam = 2020 J/kg C Lf = 335,000 J/kg Lv = 2,256,000 J/kg Find the heat necessary to turn 8 kg of ice at -8 into water at 11. c Ice = 2090 J/(kg oC) c Water = 4187 J/(kg oC) c Steam = 1996 J/(kg oC) Lf = 335,000 J/kg Lv = 2,260,000 J/kg In order to change some amount of ice at 0 deg C into steam at 110 deg C, there are four steps: • melt the ice into water • heat the water that used to be ice • boil the water into steam • heat the steam Which step requires the most heat? c Ice = 2090 J/(kg oC) c Water = 4187 J/(kg oC) c Steam = 1996 J/(kg oC) Lf = 335,000 J/kg Lv = 2,260,000 J/kg A) melt the ice into water
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Please need help with three part question on ice and temp(heat) thank you.
![How much heat is required to change 472 g of ice at -11°C to steam at 106°C?
cice = 2090 J/kg C
c water = 4184 J/kg C
c steam = 2020 J/kg C
Lf = 335,000 J/kg
Lv = 2,256,000 J/kg
Find the heat necessary to turn 8 kg of ice at -8 into water at 11.
c Ice = 2090 J/(kg oC)
c Water = 4187 J/(kg oC)
c Steam = 1996 J/(kg oC)
Lf= 335,000 J/kg
Lv = 2,260,000 J/kg
In order to change some amount of ice
four steps:
• melt the ice into water
heat the water that used to be ice
• boil the water into steam
heat the steam
Which step requires the most heat?
c Ice = 2090 J/(kg oC)
c Water = 4187 J/(kg oC)
c Steam = 1996 J/(kg oC)
Lf = 335,000 J/kg
Lv = 2,260,000 J/kg
A) melt the ice into water
B) heat the water that used to be ice
C) boil the water into steam
D) heat the steam
deg C
steam at 110 deg
the
e are](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd1d700aa-072a-4ff7-be1d-cdca0f10aa9d%2F26601b55-ae44-4bab-94ca-d0c9afad045d%2Fm9bai2r_processed.jpeg&w=3840&q=75)
Transcribed Image Text:How much heat is required to change 472 g of ice at -11°C to steam at 106°C?
cice = 2090 J/kg C
c water = 4184 J/kg C
c steam = 2020 J/kg C
Lf = 335,000 J/kg
Lv = 2,256,000 J/kg
Find the heat necessary to turn 8 kg of ice at -8 into water at 11.
c Ice = 2090 J/(kg oC)
c Water = 4187 J/(kg oC)
c Steam = 1996 J/(kg oC)
Lf= 335,000 J/kg
Lv = 2,260,000 J/kg
In order to change some amount of ice
four steps:
• melt the ice into water
heat the water that used to be ice
• boil the water into steam
heat the steam
Which step requires the most heat?
c Ice = 2090 J/(kg oC)
c Water = 4187 J/(kg oC)
c Steam = 1996 J/(kg oC)
Lf = 335,000 J/kg
Lv = 2,260,000 J/kg
A) melt the ice into water
B) heat the water that used to be ice
C) boil the water into steam
D) heat the steam
deg C
steam at 110 deg
the
e are
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