How much heat, in joules, is required to heat a 28.4-g (1-oz) ice cube from -23.0 °C to -1.0°C? Type your answer...

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### Heat Calculation for Ice Cube

**Problem Statement:**

How much heat, in joules, is required to heat a \(28.4 \, \text{g}\) (1-oz) ice cube from \(-23.0^\circ \text{C}\) to \(-1.0^\circ \text{C}\)?

**Interactive Answer Field:**

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**Explanation:**

To calculate the heat required for this temperature change, you would typically need to know the specific heat capacity of ice, which is the amount of heat per unit mass required to raise the temperature by one degree Celsius. The formula to calculate the heat required (\(q\)) is:

\[ q = m \times c \times \Delta T \]

Where:
- \( q \) is the heat absorbed (in joules),
- \( m \) is the mass of the ice (in grams),
- \( c \) is the specific heat capacity of ice (approximately \(2.09 \, \text{J/g°C}\)),
- \(\Delta T\) is the change in temperature (final temperature minus initial temperature, in degrees Celsius).
Transcribed Image Text:### Heat Calculation for Ice Cube **Problem Statement:** How much heat, in joules, is required to heat a \(28.4 \, \text{g}\) (1-oz) ice cube from \(-23.0^\circ \text{C}\) to \(-1.0^\circ \text{C}\)? **Interactive Answer Field:** Type your answer… **Explanation:** To calculate the heat required for this temperature change, you would typically need to know the specific heat capacity of ice, which is the amount of heat per unit mass required to raise the temperature by one degree Celsius. The formula to calculate the heat required (\(q\)) is: \[ q = m \times c \times \Delta T \] Where: - \( q \) is the heat absorbed (in joules), - \( m \) is the mass of the ice (in grams), - \( c \) is the specific heat capacity of ice (approximately \(2.09 \, \text{J/g°C}\)), - \(\Delta T\) is the change in temperature (final temperature minus initial temperature, in degrees Celsius).
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