How many stereoisomers exists for the following molecule? CI CH3 Br

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**How many stereoisomers exist for the following molecule?**

![Molecular Structure](imageURL) 

The molecular structure displayed consists of a six-carbon chain with the following substituents:
- A chlorine (Cl) atom attached to the second carbon.
- A methyl (CH<sub>3</sub>) group attached to the third carbon.
- A bromine (Br) atom attached to the fourth carbon.

To determine the number of stereoisomers for this molecule, we need to consider the chiral centers within the structure. A chiral center (or stereocenter) is typically a carbon atom bonded to four different groups.

The carbon atoms in positions 2, 3, and 4 seem to meet this criterion:

1. Carbon 2 is bonded to:
   - A hydrogen atom (implied in the structure but not shown)
   - A chlorine (Cl) atom
   - An ethyl group (–CH<sub>2</sub>CH<sub>2</sub>CH<sub>3</sub>)
   - A propyl group (–CH<sub>2</sub>CH<sub>3</sub>)

2. Carbon 3 is bonded to:
   - A hydrogen atom
   - A methyl (CH<sub>3</sub>) group
   - An ethyl group (–CH<sub>2</sub>–CH<sub>2</sub>Cl)
   - A butyl group (–CH<sub>2</sub>–CH<sub>2</sub>Br)

3. Carbon 4 is bonded to:
   - A hydrogen atom
   - A bromine (Br) atom
   - An ethyl group (–CH<sub>2</sub>CH<sub>3</sub>)
   - A butyl group (–CH<sub>2</sub>–CH<sub>3</sub>)

Each of these carbon atoms represents a potential chiral center. 

In general, for a molecule with n chiral centers, the number of possible stereoisomers is \( 2^n \). 

Thus, in this case, with three chiral centers, there could be up to \( 2^3 = 8 \) stereoisomers.

However, the exact number of stereoisomers also depends on symmetrical aspects and other intricacies which can sometimes reduce the number of stereoisomers.
Transcribed Image Text:**How many stereoisomers exist for the following molecule?** ![Molecular Structure](imageURL) The molecular structure displayed consists of a six-carbon chain with the following substituents: - A chlorine (Cl) atom attached to the second carbon. - A methyl (CH<sub>3</sub>) group attached to the third carbon. - A bromine (Br) atom attached to the fourth carbon. To determine the number of stereoisomers for this molecule, we need to consider the chiral centers within the structure. A chiral center (or stereocenter) is typically a carbon atom bonded to four different groups. The carbon atoms in positions 2, 3, and 4 seem to meet this criterion: 1. Carbon 2 is bonded to: - A hydrogen atom (implied in the structure but not shown) - A chlorine (Cl) atom - An ethyl group (–CH<sub>2</sub>CH<sub>2</sub>CH<sub>3</sub>) - A propyl group (–CH<sub>2</sub>CH<sub>3</sub>) 2. Carbon 3 is bonded to: - A hydrogen atom - A methyl (CH<sub>3</sub>) group - An ethyl group (–CH<sub>2</sub>–CH<sub>2</sub>Cl) - A butyl group (–CH<sub>2</sub>–CH<sub>2</sub>Br) 3. Carbon 4 is bonded to: - A hydrogen atom - A bromine (Br) atom - An ethyl group (–CH<sub>2</sub>CH<sub>3</sub>) - A butyl group (–CH<sub>2</sub>–CH<sub>3</sub>) Each of these carbon atoms represents a potential chiral center. In general, for a molecule with n chiral centers, the number of possible stereoisomers is \( 2^n \). Thus, in this case, with three chiral centers, there could be up to \( 2^3 = 8 \) stereoisomers. However, the exact number of stereoisomers also depends on symmetrical aspects and other intricacies which can sometimes reduce the number of stereoisomers.
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