How many stereoisomers are possible for a compound with the following constitution? OH Br 02 08 06 04

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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### Topic: Fischer Projections

#### Question:
How many stereoisomers are possible for a compound with the following constitution?

![Chemical Structure](Diagram showing a carbon atom bonded to -OH and -Br groups.)

#### Options:
- ○ 2
- ○ 8
- ○ 6
- ○ 4

#### Answer:
The correct answer is **4**.

#### Explanation:
The chemical structure shown is a simple representation of a carbon atom bonded to two different groups: an -OH (hydroxyl group) and a -Br (bromine atom). This type of structure suggests the presence of a chiral center, which is a carbon atom connected to four different groups. The number of possible stereoisomers for a molecule with one chiral center is determined by the formula \(2^n\), where \(n\) is the number of chiral centers. Here, \(n = 2\) as there are two bonds that can exhibit stereoisomerism, leading to \(2^2 = 4\) possible stereoisomers.

#### Hint:
Remember, each chiral center doubles the number of possible stereoisomers due to the different spatial arrangements possible around the chiral carbon(s).

#### Save for Later:
You can save this question to revisit and review your understanding of stereoisomers and Fischer projections.
Transcribed Image Text:### Topic: Fischer Projections #### Question: How many stereoisomers are possible for a compound with the following constitution? ![Chemical Structure](Diagram showing a carbon atom bonded to -OH and -Br groups.) #### Options: - ○ 2 - ○ 8 - ○ 6 - ○ 4 #### Answer: The correct answer is **4**. #### Explanation: The chemical structure shown is a simple representation of a carbon atom bonded to two different groups: an -OH (hydroxyl group) and a -Br (bromine atom). This type of structure suggests the presence of a chiral center, which is a carbon atom connected to four different groups. The number of possible stereoisomers for a molecule with one chiral center is determined by the formula \(2^n\), where \(n\) is the number of chiral centers. Here, \(n = 2\) as there are two bonds that can exhibit stereoisomerism, leading to \(2^2 = 4\) possible stereoisomers. #### Hint: Remember, each chiral center doubles the number of possible stereoisomers due to the different spatial arrangements possible around the chiral carbon(s). #### Save for Later: You can save this question to revisit and review your understanding of stereoisomers and Fischer projections.
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