How many moles of precipitate will be formed when 77.8 mL of 0.150 M AGNO3 is reacted with excess CaCl2 in the following chemical reaction? 2 AGNO3(aq) + CaCl,(aq) → 2 A9CI(s) + Ca(NO3)2(aq)
How many moles of precipitate will be formed when 77.8 mL of 0.150 M AGNO3 is reacted with excess CaCl2 in the following chemical reaction? 2 AGNO3(aq) + CaCl,(aq) → 2 A9CI(s) + Ca(NO3)2(aq)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Precipitate Calculation in a Chemical Reaction**
**Question 6 of 39**
**Problem Statement:**
Calculate the moles of precipitate formed when 77.8 mL of 0.150 M AgNO₃ is reacted with an excess of CaCl₂ in the following chemical reaction:
\[ 2 \, \text{AgNO}_3(\text{aq}) + \text{CaCl}_2(\text{aq}) \rightarrow 2 \, \text{AgCl}(\text{s}) + \text{Ca(NO}_3\text{)}_2(\text{aq}) \]
**Instruction:**
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Transcribed Image Text:**Precipitate Calculation in a Chemical Reaction**
**Question 6 of 39**
**Problem Statement:**
Calculate the moles of precipitate formed when 77.8 mL of 0.150 M AgNO₃ is reacted with an excess of CaCl₂ in the following chemical reaction:
\[ 2 \, \text{AgNO}_3(\text{aq}) + \text{CaCl}_2(\text{aq}) \rightarrow 2 \, \text{AgCl}(\text{s}) + \text{Ca(NO}_3\text{)}_2(\text{aq}) \]
**Instruction:**
Enter your answer in the space provided below, using the keypad to input numbers.
**Keypad:**
- Numerical digits (1-9, 0)
- Decimal point (.)
- Positive/negative sign (+/-)
- Backspace (×)
- Clear (C)
- Exponentiation (x 10^□)
**Note:**
For additional resources, tap the orange bar at the bottom of the interface.
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