How many moles of precipitate will be formed when 77.8 mL of 0.150 M AGNO3 is reacted with excess CaCl2 in the following chemical reaction? 2 AGNO3(aq) + CaCl,(aq) → 2 A9CI(s) + Ca(NO3)2(aq)

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**Precipitate Calculation in a Chemical Reaction**

**Question 6 of 39**

**Problem Statement:**
Calculate the moles of precipitate formed when 77.8 mL of 0.150 M AgNO₃ is reacted with an excess of CaCl₂ in the following chemical reaction:

\[ 2 \, \text{AgNO}_3(\text{aq}) + \text{CaCl}_2(\text{aq}) \rightarrow 2 \, \text{AgCl}(\text{s}) + \text{Ca(NO}_3\text{)}_2(\text{aq}) \]

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Transcribed Image Text:**Precipitate Calculation in a Chemical Reaction** **Question 6 of 39** **Problem Statement:** Calculate the moles of precipitate formed when 77.8 mL of 0.150 M AgNO₃ is reacted with an excess of CaCl₂ in the following chemical reaction: \[ 2 \, \text{AgNO}_3(\text{aq}) + \text{CaCl}_2(\text{aq}) \rightarrow 2 \, \text{AgCl}(\text{s}) + \text{Ca(NO}_3\text{)}_2(\text{aq}) \] **Instruction:** Enter your answer in the space provided below, using the keypad to input numbers. **Keypad:** - Numerical digits (1-9, 0) - Decimal point (.) - Positive/negative sign (+/-) - Backspace (×) - Clear (C) - Exponentiation (x 10^□) **Note:** For additional resources, tap the orange bar at the bottom of the interface.
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