How many moles of NHs gas form when 32.4L of H2 gas completely reacts at STP according to the following reaction? Remember 1 mol of an ideal gas has a volume of 22.4 L at STP. N:(g) + 3 H2(g) 2 NH.(g) -

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**Chemistry Problem: Gas Stoichiometry at STP**

**Problem Statement:**
How many moles of NH₃ gas form when 32.4 L of H₂ gas completely reacts at STP, according to the following reaction? Remember, 1 mol of an ideal gas has a volume of 22.4 L at STP.

**Chemical Reaction:**
\[ \text{N}_2(\text{g}) + 3\text{H}_2(\text{g}) \rightarrow 2\text{NH}_3(\text{g}) \]

**Calculation Setup:**
To solve this, use the stoichiometric relationship between H₂ and NH₃ in the balanced equation. We'll also use the volume of the gas at STP to convert between liters and moles.

**Solution Layout:**
1. **Starting Amount:** The volume of H₂ is given as 32.4 L.
2. **Conversion and Stoichiometry:**  
   - Convert liters of H₂ to moles using the molar volume at STP (22.4 L/mol).
   - Use the stoichiometric coefficients (3 mol H₂ : 2 mol NH₃) to determine moles of NH₃ produced.

**Calculation Tools:**
- Use the tools for starting amount, conversion factors, and stoichiometric ratios displayed in the interface.
- Boxes provided to input values and perform calculations.

**Buttons and Values:**
- The interface includes buttons with numerical values such as 17.03, 3, 2.02, 32.4, 22.4, etc., and operations like multiplication to assist with calculations.
- There is an "Add Factor" section for additional calculations if needed.
- An "Answer" section where the result will be displayed.
- A "Reset" button to start a new calculation if necessary.
Transcribed Image Text:**Chemistry Problem: Gas Stoichiometry at STP** **Problem Statement:** How many moles of NH₃ gas form when 32.4 L of H₂ gas completely reacts at STP, according to the following reaction? Remember, 1 mol of an ideal gas has a volume of 22.4 L at STP. **Chemical Reaction:** \[ \text{N}_2(\text{g}) + 3\text{H}_2(\text{g}) \rightarrow 2\text{NH}_3(\text{g}) \] **Calculation Setup:** To solve this, use the stoichiometric relationship between H₂ and NH₃ in the balanced equation. We'll also use the volume of the gas at STP to convert between liters and moles. **Solution Layout:** 1. **Starting Amount:** The volume of H₂ is given as 32.4 L. 2. **Conversion and Stoichiometry:** - Convert liters of H₂ to moles using the molar volume at STP (22.4 L/mol). - Use the stoichiometric coefficients (3 mol H₂ : 2 mol NH₃) to determine moles of NH₃ produced. **Calculation Tools:** - Use the tools for starting amount, conversion factors, and stoichiometric ratios displayed in the interface. - Boxes provided to input values and perform calculations. **Buttons and Values:** - The interface includes buttons with numerical values such as 17.03, 3, 2.02, 32.4, 22.4, etc., and operations like multiplication to assist with calculations. - There is an "Add Factor" section for additional calculations if needed. - An "Answer" section where the result will be displayed. - A "Reset" button to start a new calculation if necessary.
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