How many moles of NH3 can be produced from 3.76 moles of nitrogen in the following reaction: N2 (g) + 3 H2 (g) → 2 NH, (g) ->

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**Stoichiometry Problem: Calculating Moles in a Chemical Reaction**

**Problem Statement:**

How many moles of \( \text{NH}_3 \) can be produced from 3.76 moles of nitrogen in the following reaction:

\[ \text{N}_2 (g) + 3 \text{H}_2 (g) \rightarrow 2 \text{NH}_3 (g) \]

**Explanation of the Reaction:**

In this balanced chemical equation, one mole of nitrogen gas (\( \text{N}_2 \)) reacts with three moles of hydrogen gas (\( \text{H}_2 \)) to produce two moles of ammonia (\( \text{NH}_3 \)). This reaction demonstrates the stoichiometric relationship between the reactants and the product. By using these relationships, you can calculate the amount of product formed from a given amount of reactant.
Transcribed Image Text:**Stoichiometry Problem: Calculating Moles in a Chemical Reaction** **Problem Statement:** How many moles of \( \text{NH}_3 \) can be produced from 3.76 moles of nitrogen in the following reaction: \[ \text{N}_2 (g) + 3 \text{H}_2 (g) \rightarrow 2 \text{NH}_3 (g) \] **Explanation of the Reaction:** In this balanced chemical equation, one mole of nitrogen gas (\( \text{N}_2 \)) reacts with three moles of hydrogen gas (\( \text{H}_2 \)) to produce two moles of ammonia (\( \text{NH}_3 \)). This reaction demonstrates the stoichiometric relationship between the reactants and the product. By using these relationships, you can calculate the amount of product formed from a given amount of reactant.
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