How many moles of Mg3P2(s) can be produced from the reaction of0.14 mol Mg(s) with 0.020 mol P4(s)?6 Mg(s) + P4(s) → 2 Mg3P₂(s)O 0.047 molO 0.14 molO 0.020 molO 0.42 molO 0.040 mol A solution of sodium oxalate (Na2C2O4) in acidic solution is titratedwith a solution of potassium permanganate (KMnO4) according tothe following balanced chemical equation:2KMnO4(aq) + 8H₂SO4(aq) + 5Na2C2O4(aq) → 2MnSO4(aq) +8H₂O()+10CO2(g) + 5Na2SO4(aq) + K₂SO4(aq)What volume of 0.0206 M KMnO4 is required to titrate 50.0 mlsolution of 0.0262M Na2C2O4?O 50.0 mLO 25.5 mL3.42 mLO8.54 mLO63.8 mL

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How many moles of Mg3P2(s) can be produced from the reaction of 0.14 mol Mg(s) with 0.020 mol P4(s)? 6 Mg(s) + P4(s) → 2 Mg3P₂(s) O 0.047 mol O 0.14 mol O 0.020 mol O 0.42 mol O 0.040 mol

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

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How many moles of Mg3P2(s) can be produced from the reaction of
0.14 mol Mg(s) with 0.020 mol P4(s)?
6 Mg(s) + P4(s) → 2 Mg3P₂(s)
O 0.047 mol
O 0.14 mol
O 0.020 mol
O 0.42 mol
O 0.040 mol

A solution of sodium oxalate (Na2C2O4) in acidic solution is titrated
with a solution of potassium permanganate (KMnO4) according to
the following balanced chemical equation:
2KMnO4(aq) + 8H₂SO4(aq) + 5Na2C2O4(aq) → 2MnSO4(aq) +
8H₂O()+10CO2(g) + 5Na2SO4(aq) + K₂SO4(aq)
What volume of 0.0206 M KMnO4 is required to titrate 50.0 ml
solution of 0.0262M Na2C2O4?
O 50.0 mL
O 25.5 mL
3.42 mL
O8.54 mL
O63.8 mL

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