How many moles of Mg*2 in 6.00 mL of a 6.0N Mg3(PO4)2 sOolution ? First we have to convert moles into equivalents Mg3(PO4)2 3 Mg*2 2 PO43 + 1 mol = equivalents 1 mol MP = mol Mg*2 eq mol (6.00 x 103 L)(- ) = eq MP (- -) = eq mol Mg*2 mol MP)(-- mol Mg*2 mol MP а. 250. b. 100.0 с. 2 d. 30.00 е. 6 f. 24 g. 3 h. 36 i. 18.0 j. 1 k. 6.00 x 103 I. 3.60 x 102 m. 6.00 x 10-2 n. 5 о. 3.0 х 10:2 р. 1.80 х 102 9. 7.65 х 10:10 r. 2.63 s. 7.89 t. 5.26 u. 1012 v. 109 w. 106 х. 103 у. 95.21 z. 10

How many moles of Mg2 in 6.00 mL of a 6.0N Mg3(PO4)2 sOolution ? First we have to convert moles into equivalents Mg3(PO4)2 3 Mg2 2 PO43 + 1 mol = equivalents 1 mol MP = mol Mg2 eq mol (6.00 x 103 L)(- ) = eq MP (- -) = eq mol Mg2 mol MP)(-- mol Mg*2 mol MP а. 250. b. 100.0 с. 2 d. 30.00 е. 6 f. 24 g. 3 h. 36 i. 18.0 j. 1 k. 6.00 x 103 I. 3.60 x 102 m. 6.00 x 10-2 n. 5 о. 3.0 х 10:2 р. 1.80 х 102 9. 7.65 х 10:10 r. 2.63 s. 7.89 t. 5.26 u. 1012 v. 109 w. 106 х. 103 у. 95.21 z. 10

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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