Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:How many grams of solute are present in 165 mL of 0.410 M KBr?
mass of solute:
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Expert Solution

Step 1: Calculation of the moles of solute(KBr)
Given,
volume of solution = 165 mL = 165 mL x ( 1 L / 1000 mL) = 0.165 L
concentration of KBr solution = 0.410 M
we know,
=> concentration of KBr solution = moles of solute (KBr) / volume of solution
on substituting the value
=> 0.410 mol/L = moles of solute(KBr) / 0.165 L
=> moles of solute(KBr) = 0.410 mol/L x 0.165 L = 0.06765 mol
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