How many moles of H,SO, are required to completely react with 7.20 mol of Al according to the balanced chemical reaction: 2 Al(s) + 3 H,SO,(aq) → Al,(SO,),(aq) + 3 H,(g)
How many moles of H,SO, are required to completely react with 7.20 mol of Al according to the balanced chemical reaction: 2 Al(s) + 3 H,SO,(aq) → Al,(SO,),(aq) + 3 H,(g)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Question 17 of 28: Reaction Stoichiometry Problem**
**Problem Statement:**
Calculate how many moles of H₂SO₄ are required to completely react with 7.20 mol of Al according to the balanced chemical equation provided.
**Balanced Chemical Equation:**
\[ 2 \text{Al(s)} + 3 \text{H}_2\text{SO}_4\text{(aq)} \rightarrow \text{Al}_2(\text{SO}_4)_3\text{(aq)} + 3 \text{H}_2\text{(g)} \]
**Calculation Approach:**
1. **Starting Amount:**
- Input the given amount of Al, which is 7.20 mol.
2. **Conversion Setup:**
- Using stoichiometry, set up your conversion factor based on the balanced equation. The reaction shows that 2 moles of Al react with 3 moles of H₂SO₄.
3. **Diagram Explanation:**
- On the left, a box labeled "Starting Amount" is meant for inputting the initial quantity of reactant (7.20 mol of Al).
- To the right, there is a multiplication setup to guide through stoichiometric conversion.
**Values Given for Conversion:**
- Atomic and molecular masses and molar conversions are provided as follows:
- Molar mass of substances (98.08 g/mol for Al₂(SO₄)₃, 342.14 g/mol, etc.)
- Common conversion factors (6.022 × 10²³ for Avogadro's number)
4. **Answer Calculation:**
- Use the mole ratio from the balanced equation (3 mol H₂SO₄ / 2 mol Al) to perform the conversion from moles of Al to moles of H₂SO₄.
This layout aids in visually organizing the stoichiometric problem for an educational platform, ensuring clarity and structured problem-solving.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8ef087f6-f2d1-423b-957c-64dac1e9f591%2Fb14f3d71-54a5-4236-a2fb-d0bf77827a5f%2Fj1wu7us_processed.png&w=3840&q=75)
Transcribed Image Text:**Question 17 of 28: Reaction Stoichiometry Problem**
**Problem Statement:**
Calculate how many moles of H₂SO₄ are required to completely react with 7.20 mol of Al according to the balanced chemical equation provided.
**Balanced Chemical Equation:**
\[ 2 \text{Al(s)} + 3 \text{H}_2\text{SO}_4\text{(aq)} \rightarrow \text{Al}_2(\text{SO}_4)_3\text{(aq)} + 3 \text{H}_2\text{(g)} \]
**Calculation Approach:**
1. **Starting Amount:**
- Input the given amount of Al, which is 7.20 mol.
2. **Conversion Setup:**
- Using stoichiometry, set up your conversion factor based on the balanced equation. The reaction shows that 2 moles of Al react with 3 moles of H₂SO₄.
3. **Diagram Explanation:**
- On the left, a box labeled "Starting Amount" is meant for inputting the initial quantity of reactant (7.20 mol of Al).
- To the right, there is a multiplication setup to guide through stoichiometric conversion.
**Values Given for Conversion:**
- Atomic and molecular masses and molar conversions are provided as follows:
- Molar mass of substances (98.08 g/mol for Al₂(SO₄)₃, 342.14 g/mol, etc.)
- Common conversion factors (6.022 × 10²³ for Avogadro's number)
4. **Answer Calculation:**
- Use the mole ratio from the balanced equation (3 mol H₂SO₄ / 2 mol Al) to perform the conversion from moles of Al to moles of H₂SO₄.
This layout aids in visually organizing the stoichiometric problem for an educational platform, ensuring clarity and structured problem-solving.
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