How many moles of H,SO, are required to completely react with 7.20 mol of Al according to the balanced chemical reaction: 2 Al(s) + 3 H,SO,(aq) → Al,(SO,),(aq) + 3 H,(g)

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Chapter1: Chemical Foundations
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**Question 17 of 28: Reaction Stoichiometry Problem**

**Problem Statement:**
Calculate how many moles of H₂SO₄ are required to completely react with 7.20 mol of Al according to the balanced chemical equation provided.

**Balanced Chemical Equation:**
\[ 2 \text{Al(s)} + 3 \text{H}_2\text{SO}_4\text{(aq)} \rightarrow \text{Al}_2(\text{SO}_4)_3\text{(aq)} + 3 \text{H}_2\text{(g)} \]

**Calculation Approach:**

1. **Starting Amount:**
   - Input the given amount of Al, which is 7.20 mol.

2. **Conversion Setup:**
   - Using stoichiometry, set up your conversion factor based on the balanced equation. The reaction shows that 2 moles of Al react with 3 moles of H₂SO₄.

3. **Diagram Explanation:**
   - On the left, a box labeled "Starting Amount" is meant for inputting the initial quantity of reactant (7.20 mol of Al).
   - To the right, there is a multiplication setup to guide through stoichiometric conversion.

**Values Given for Conversion:**
   - Atomic and molecular masses and molar conversions are provided as follows:
     - Molar mass of substances (98.08 g/mol for Al₂(SO₄)₃, 342.14 g/mol, etc.)
     - Common conversion factors (6.022 × 10²³ for Avogadro's number)

4. **Answer Calculation:**
   - Use the mole ratio from the balanced equation (3 mol H₂SO₄ / 2 mol Al) to perform the conversion from moles of Al to moles of H₂SO₄.

This layout aids in visually organizing the stoichiometric problem for an educational platform, ensuring clarity and structured problem-solving.
Transcribed Image Text:**Question 17 of 28: Reaction Stoichiometry Problem** **Problem Statement:** Calculate how many moles of H₂SO₄ are required to completely react with 7.20 mol of Al according to the balanced chemical equation provided. **Balanced Chemical Equation:** \[ 2 \text{Al(s)} + 3 \text{H}_2\text{SO}_4\text{(aq)} \rightarrow \text{Al}_2(\text{SO}_4)_3\text{(aq)} + 3 \text{H}_2\text{(g)} \] **Calculation Approach:** 1. **Starting Amount:** - Input the given amount of Al, which is 7.20 mol. 2. **Conversion Setup:** - Using stoichiometry, set up your conversion factor based on the balanced equation. The reaction shows that 2 moles of Al react with 3 moles of H₂SO₄. 3. **Diagram Explanation:** - On the left, a box labeled "Starting Amount" is meant for inputting the initial quantity of reactant (7.20 mol of Al). - To the right, there is a multiplication setup to guide through stoichiometric conversion. **Values Given for Conversion:** - Atomic and molecular masses and molar conversions are provided as follows: - Molar mass of substances (98.08 g/mol for Al₂(SO₄)₃, 342.14 g/mol, etc.) - Common conversion factors (6.022 × 10²³ for Avogadro's number) 4. **Answer Calculation:** - Use the mole ratio from the balanced equation (3 mol H₂SO₄ / 2 mol Al) to perform the conversion from moles of Al to moles of H₂SO₄. This layout aids in visually organizing the stoichiometric problem for an educational platform, ensuring clarity and structured problem-solving.
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