How many milliliters of 0.475 M KOH solution are needed to completely neutralize 38.0 mL of 0.231 M HI solution? The reaction is KOH(aq) + HI(ag) → KI(aq) + H2O(1) i mL eTexthook and Media

Q: What volume in mL of 0.025 M HBr solution is to be required to titrations 125mL of a 0.049 M NaOH…

A: As per the reaction,  NaOH(aq) + HBr(aq) -> NaBr(aq)+H2O(I) we can see that 1 mole of HBr is…

Q: HCl(aq)+NaHCO3(aq)=NaCl(aq)+H2O(l)+CO2(g) The CO2 gas is a product   Suppose indigestion can be…

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Q: The titration of 25.00 mL of an unknown concentration of H2SO4 solution requires 32.28 mL of 0.420 M…

A: Given, reaction : H2SO4(aq)+2LiOH(aq)→Li2SO4(aq)+2H2O(l)

Q: What volume, in mL, of 1.78 M LiOH(aq) is needed to COMPLETELY NEUTRALIZE 125. mL of 1.38M H2C2O4…

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Q: What volume of 0.150 M HNO3 solution is needed to neutralize 45.0 ml of a 0.550 M KOH solution?…

A: The neutralization reaction between KOH and HNO3 takes place as follows: HNO3(aq)+KOH(aq) ->…

Q: Given a balanced chemical equation between H2SO4(aq) and KOH(aq)       H2SO4(aq) + 2 KOH(aq) →…

A: The balanced reaction taking place is given as, => H2SO4 (aq) + 2 KOH (aq) → K2SO4 (aq) + 2 H2O…

Q: A 25.00-ml sample of an unknown HCIO, solution requires ti- tration with 22.62 mL of 0.2000 M NAOH…

A: The molarity of a solution measures the concentration of solution in mol/L. The molarity of an…

Q: 25.0 mL of 0.212 M NaOH is neutralized by 17.7  mL of an HCl solution according to the equation…

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Q: 2. Dilute sulphuric acid is a strong acid. (a) What is meant by a "strong" acid? (b) A student…

A: Given: Volume of dilute sulfuric acid = 25.0 cm3 = 25.0 mL   Trial-1 Trial-2 Trial-3 Trial-4…

Q: Consider the following: 50 mL of a 1.067 M solution of HCI was diluted to 250 mL. The diluted HCI…

A: 50 mL of a 1.067 M solution of HCl was diluted to 250 mL . 25.00 mL of these diluted HCl solution…

Q: Consider an acid-base neutralization reaction: H2SO4(aq) + 2 NAOH(aq) NazSO4(aq) + 2 H2O(1) --->…

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Q: In standardizing a solution of NaOH (40 g/mol) against 1.431 g of KHP (204.22 g/mol) the analyst…

A: Volumetric analysis is a method in which the volume of a substance is determined by measuring its…

Q: What volume of 0.1292 M Ba(OH)2 would neutralize 50.00 mL of 0.1000 M HCl solution? Ba(OH)2(aq) +…

A: From the above reaction we can see that 2 moles of HCl required 1 mole of Ba(OH)2  Hence moles of…

Q: What is the volume, in milliliters, of a 0.350 M KOH needed to completely neutralize 15.0 mL of a…

A: Introduction :  We need to find the volume of KOH required to completely neutralise H2SO4 . Given  :…

Q: Assuming that the following reaction occurred based on the balanced equation: 2AgNO3 (aq) + MgCl2…

A: given balanced reaction : 2AgNO3(aq) +MgCl2 (aq)→2AgCl (s) +Mg(NO3)2 (aq) given values : for AgNO3 :…

Q: volume of 1.04 M sulfuric acid that would be needed to neutralize 53.1 mL of a 3.06 M aqueous…

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Q: What is the percentage of Na2CO3 in the mix?

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Q: What volume, in mL, of 0.300 M HCl is required to react completely with 1.50 g of sodium hydrogen…

A: We have 0.3 M HCl , 1.5g of sodium bicarbonate. We have reaction of sodium bicarbonate with HCl, we…

Q: Alanine, abbreviated HAla, is an amino acid in protein. If 21.05 mL of 0.145 M NaOH neutralizes…

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Q: What volume (in mL) of 0.034 M HBr solution is be required to titrate 125 mL of a 0.033 M  NaOH…

A: From the chemical equation for the reaction between the NaOH and HBr, it is cleared that the number…

Q: Through this reaction HCl(aq) + NaHCO3(aq)— NaCl(aq) +H2O(l) +CO2(g). The CO2 gas produced is what…

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Q: How many milliliters of 0.145 M HCl are needed to completely neutralize 46.0 mL of 0.110 M Ba(OH)2…

A: First the reaction between given acid and base is noted as shown below, 2HCl + Ba(OH)2→BaCl2 + 2H2O

Q: 5. What volume, in mL, of 0.850 M HCl is required to neutralize 0.0200 L of 0.1033 M NaOH? HCl(aq) +…

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Q: How many milliliters of 0.094 M NaOH are needed to completely neutralize 26.6 mL of 0.210 M…

A: Number of moles = Molarity x Volume (L) From the balance equation it is evident that 2 moles of NaOH…

Q: what volume in mL of 0.026 M HBr solution is to be required to titrate 125mL of a 0.032 M NaOH…

A: Record the given data: Concentration of HBr = 0.026 M Concentration of NaOH  = 0.032 M Volume of…

Q: How many milliliters of 0.295 M NaOH solution are needed to completely neutralize 21.8 mL of 0.276 M…

A: The balanced reaction is:

Q: How many ml of 0.375M HNO3 are needed to completely neutralize 25.0ml of 0.101M Ba(OH)2 ? 2HNO3 (aq)…

A: The reaction is neutralization  calculation of neutralization based on gram equivalent concept…

Q: Given the following balanced chemical reaction, wha the net ionic equation. H2C2O4 (aq) + 2 LIOH…

A: An ionic equation is a chemical equation in which dissolved ionic compounds are represented as free…

Q: molarity

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Q: A 1.5 g sample of HCI is dissolved in water and titrated with 1.5 M NAOH. Considering the…

A: given Mass of HCl = 1.5 g Molarity of NaOH = 1.5 M

Q: HCl(aq) + KOH(aq) → H 2O(ℓ) + KCl(aq) How many mL of 0.556 M HCl will be required to neutralize…

A: According to the given chemical equation for the reaction between HCl and KOH, 0.658 moles of HCl…

Q: Calculate the number of milliliters (mL) of a 0.125 M solution of KOH will be required to titrate…

A: Molarity is defined as number of mole of solute divide by volume of solution in liter

Q: KOH(aq) → K2SO4(aq) + 2 H2O(l) What volume (in mL) of 0.78 M H2SO4(aq) solution is necessary to…

A: Equal both equivalent  Equivalent=molarity×n factor×volume n factor is total no of  replacable H+…

Q: 4.208 g of potassium hydroxide (KOH) is dissolved in 100 mL of water. What volume (in mL) of a 0.500…

A: Given: The balanced equation for the neutralization of KOH by H3PO4: 3KOH(aq) + H3PO4(aq) -->…

Q: A certain brand of vinegar is analyzed for its acetic acid content by titration with 0.2 moles/liter…

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Q: How many mL of 0.244 M NaOH(aq) solution are required to neutralize 1.89 g of KHC8H4O4 (MM = 204.22…

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Q: 5. It takes 125.0 mL of 3.5 M hydrobromic acid to neutralize 75.0 mL of lithium hydroxide. What is…

A: Answer:- this question is answered by using the simple concept of calculation of molarity of acid…

Q: For numbers 8-10 (3pts) Show your solution to the following and box your answer. A soda mint tablet…

A: Given -> Volume of HCl = 30.5 ml Molarity of HCl= 0.135 M