How many liters of CH.OH gas are formed when 3.20 L of H: gas are completely reacted at STP according to the following chemical reaction? Remember 1 mol of an ideal gas has a volume of 22.4 L at STP. Co(g) + 2 H:(g) → CH:OH(g)

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Chapter1: Chemical Foundations
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**Problem Statement:**  
How many liters of CH₃OH gas are formed when 3.20 L of H₂ gas are completely reacted at STP according to the following chemical reaction? Remember 1 mol of an ideal gas has a volume of 22.4 L at STP.

**Chemical Reaction:**  
CO(g) + 2 H₂(g) → CH₃OH(g)

**Visual Aid:**  
- **Input Section:** There are blank input fields labeled "STARTING AMOUNT" for entering data. 
- **Multiplication Section:** This section includes two side-by-side brackets where users can input factors to calculate the resulting volume of CH₃OH.

In the context of this problem, you will need to use the stoichiometry of the reaction and the ideal gas law concept at STP to solve for the desired volume of CH₃OH gas.
Transcribed Image Text:**Problem Statement:** How many liters of CH₃OH gas are formed when 3.20 L of H₂ gas are completely reacted at STP according to the following chemical reaction? Remember 1 mol of an ideal gas has a volume of 22.4 L at STP. **Chemical Reaction:** CO(g) + 2 H₂(g) → CH₃OH(g) **Visual Aid:** - **Input Section:** There are blank input fields labeled "STARTING AMOUNT" for entering data. - **Multiplication Section:** This section includes two side-by-side brackets where users can input factors to calculate the resulting volume of CH₃OH. In the context of this problem, you will need to use the stoichiometry of the reaction and the ideal gas law concept at STP to solve for the desired volume of CH₃OH gas.
Expert Solution
Step 1

To calculate the volume ( litres) of CH3OH ( g) formed , we would first calculate the moles of H2 reacted . From it we would calculate moles of CH3OH formed using mole ratio between them . Then we would calculate volume from the value of moles .

 

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