How many liters of 0.305 M K:PO. solution are necessary to completely react with 187 mL of 0.0184 M NICI according to the balanced chemical reaction: 2 KPO-(aq) + 3 NICI:(aq) –→ Ni>(PO«):(s) + KCI(aq)

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Question 10 of 26
How many liters of 0.305 M KPO: solution are necessary to completely react with
187
mL of 0.0184 M NIC2 according to the balanced chemical reaction:
2
KPO4(ag) +
3
NiCl:(aq) → Nis:(PO.):(s) +
6
KCI(aq)
X
0.00752
LKPO4
STARTING AMOUNT
= 0.00752 L KPO4
0.0113
1
6.022 x 1023
0.305
187
1000
0.001
3
0.00376
0.00752
0.0184
7.52
mL KPO4
M KPO4
M NICI2
g KsPO4
L KPO4
mol KsPO4
mol NiCl2
mL NiCl2
L NIC.
g NiCk
Transcribed Image Text:Question 10 of 26 How many liters of 0.305 M KPO: solution are necessary to completely react with 187 mL of 0.0184 M NIC2 according to the balanced chemical reaction: 2 KPO4(ag) + 3 NiCl:(aq) → Nis:(PO.):(s) + 6 KCI(aq) X 0.00752 LKPO4 STARTING AMOUNT = 0.00752 L KPO4 0.0113 1 6.022 x 1023 0.305 187 1000 0.001 3 0.00376 0.00752 0.0184 7.52 mL KPO4 M KPO4 M NICI2 g KsPO4 L KPO4 mol KsPO4 mol NiCl2 mL NiCl2 L NIC. g NiCk
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