Please fill in the boxes...you can only use the given boxes under the solution map. I need to demonstrate all the units canceling eachother out Question 10 of 26How many liters of 0.305 M KPO: solution are necessary to completely react with187mL of 0.0184 M NIC2 according to the balanced chemical reaction:2KPO4(ag) +3NiCl:(aq) → Nis:(PO.):(s) +6KCI(aq)X0.00752LKPO4STARTING AMOUNT= 0.00752 L KPO40.011316.022 x 10230.30518710000.00130.003760.007520.01847.52mL KPO4M KPO4M NICI2g KsPO4L KPO4mol KsPO4mol NiCl2mL NiCl2L NIC.g NiCk

Answered: Image /qna-images/answer/a0769cf5-09db-4129-9f50-98bed00e31c0.jpg

How many liters of 0.305 M K:PO. solution are necessary to completely react with 187 mL of 0.0184 M NICI according to the balanced chemical reaction: 2 KPO-(aq) + 3 NICI:(aq) –→ Ni>(PO«):(s) + KCI(aq)

How many liters of 0.305 M K:PO. solution are necessary to completely react with 187 mL of 0.0184 M NICI according to the balanced chemical reaction: 2 KPO-(aq) + 3 NICI:(aq) –→ Ni>(PO«):(s) + KCI(aq)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Please fill in the boxes...you can only use the given boxes under the solution map. I need to demonstrate all the units canceling eachother out

Question 10 of 26
How many liters of 0.305 M KPO: solution are necessary to completely react with
187
mL of 0.0184 M NIC2 according to the balanced chemical reaction:
2
KPO4(ag) +
3
NiCl:(aq) → Nis:(PO.):(s) +
6
KCI(aq)
X
0.00752
LKPO4
STARTING AMOUNT
= 0.00752 L KPO4
0.0113
1
6.022 x 1023
0.305
187
1000
0.001
3
0.00376
0.00752
0.0184
7.52
mL KPO4
M KPO4
M NICI2
g KsPO4
L KPO4
mol KsPO4
mol NiCl2
mL NiCl2
L NIC.
g NiCk

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