How many grams of X2Y (MW = 57.58) is needed to prepare 410 mL of 0.187 M solution ? Answer in 2 decimal places. no units required

Introductory Chemistry For Today
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Author:Seager
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Chapter7: Solutions And Colloids
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How many grams of X2Y (MW = 57.58) is needed to prepare 410 mL of 0.187 M solution ?

Answer in 2 decimal places. no units required

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