How many grams of N2 are needed to make 444 g of NBr3 ? N2 + 3 Br2 → 2 NBr3 + 44.0 kJ The molar mass of NBr3 is 253.719 g and the molar mass of N2 is 28.013 g Blank 1. Fill in the blank, read surrounding text. mol NBr3 (444 g NBr3)(–––––––––––––––––––––––––) = Blank 2. Fill in the blank, read surrounding text. mol NBr3
How many grams of N2 are needed to make 444 g of NBr3 ?
N2 + 3 Br2 → 2 NBr3 + 44.0 kJ
The molar mass of NBr3 is 253.719 g and the molar mass of N2 is 28.013 g
Blank 1. Fill in the blank, read surrounding text. mol NBr3
(444 g NBr3)(–––––––––––––––––––––––––) = Blank 2. Fill in the blank, read surrounding text. mol NBr3
Blank 3. Fill in the blank, read surrounding text. g NBr3
Blank 4. Fill in the blank, read surrounding text. mol N2
Blank 5. Fill in the blank, read surrounding text. mol NBr3 (–––––––––––––––––––––––––) = Blank 6. Fill in the blank, read surrounding text. mol N2
Blank 7. Fill in the blank, read surrounding text. mol NBr3
Blank 8. Fill in the blank, read surrounding text. g N2
Blank 9. Fill in the blank, read surrounding text. mol N2 (–––––––––––––––––––––––––) = Blank 10. Fill in the blank, read surrounding text. g N2
Blank 11. Fill in the blank, read surrounding text. mol N2
a. 1 b. 2 c. 3 d. 4 e. 5 f. 253.719 g. 3.38 x 100 h. 3.26 x 103 i. 44.0 j. 1.33 x 10-2
k. 9.77 x 103 l. 4.44 x 102 m. 6.66 x 102 n. 500.0 o. 556 p. 90.0 q. 3.2852 r. 159.81
s. 28.013 t. 1.750 u. 0.8750 v. 13.0 w. 0.46306 x. 1.3892 y. 24.5 z. 38.5 aa. 2.190
bb. evolved cc. absorbed dd. exothermic ee. endothermic
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