How many grams of iron(II) carbonate, FeCO3 (formula weight = 115.8 g/mol), are precipitated when 125 mL of 0.285 M Fe(NO3)2 (ag) are mixed with an excess of 0.512M K-CO3 (ag) solution? The reaction is: Fe(NO3)2 (aq) + K2CO3(aq) › FeCO3 (s) + 2KNO3 (aq)
How many grams of iron(II) carbonate, FeCO3 (formula weight = 115.8 g/mol), are precipitated when 125 mL of 0.285 M Fe(NO3)2 (ag) are mixed with an excess of 0.512M K-CO3 (ag) solution? The reaction is: Fe(NO3)2 (aq) + K2CO3(aq) › FeCO3 (s) + 2KNO3 (aq)
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.53PAE: The ore cinnabar (HgS) is an important source of mercury. Cinnabar is a red solid whose solubility...
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How many grams of iron(II) carbonate, FeCO3 (formula weight = 115.8 g/mol),
are precipitated when 125 mL of 0.285 M Fe(NO3)2 (ag) are mixed with an excess of 0.512M K-CO3 (ag) solution? The reaction is:
Fe(NO3)2 (aq) + K2CO3(aq)
› FeCO3 (s) + 2KNO3 (aq)
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