How many grams of Cl2 are needed to form 84.4 g of AlCl3? 2Al(s)+3Cl2(g)⟶2AlCl3(s)   Step 1: Show the strategy for solving this problem. grams AlCl3 -----> _____________ ----> grams Cl2------> ____________ Answer Bank: grams AlCl3  , moles Al   ,  grams Cl2 ,  grams Al,  moles Cl2,  moles AlCl3   Step 2: Show the conversions required to solve this problem and calculate the grams of Cl2.  84.4 g AlCl3  x  ----------  x ----------- = ----------   = ________ g Cl2                          -----------    ---------- = ----------- Answer Bank:  26.98g Al  , 1 mole Al,  2 moles Al,  70.90g Cl2,  1 mole Cl2,   3 moles Cl2,   133.33g AlCl3,   1 moles AlCl3,   2 moles AlCl3

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Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.