Correct 1. Calculate the amounts of each reactant. 2. Compare the ratio of reactants amounts to the stoichiometric ratio defined by the equation. 1 mol Ss 256.5 g 20.0 g Ss x = 0.0780 mol Ss 1 mol Cl2 70.90 g 88.0 g Cl2 x = 1.24 mol Cl, 1.24 mol Cl 15.9 mol Cl2 4 mol Cl2 0.0780 mol Sg 1 mol Ss 1 mol S8 So Sg is the limiting reactant. b What is the theoretical yield of S2 Cl2 ? Theoretical yield = g Submit

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Chapter1: Chemical Foundations
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1. Calculate the amounts of each reactant.
2. Compare the ratio of reactants amounts to the stoichiometric ratio defined by the equation.
1 mol Ss
256.5 g
20.0 g Ss x
0.0780 mol S8
1 mol Cl2
88.0 g Cl2 x
1.24 mol Cl2
70.90 g
4 mol Cl2
15.9 mol Cl2
1 mol Sg
1.24 mol Cl2
0.0780 mol S8
1 mol Sg
So Sg is the limiting reactant.
(b What is the theoretical yield of S, Cl2 ?
Theoretical yield
Submit
Transcribed Image Text:Correct 1. Calculate the amounts of each reactant. 2. Compare the ratio of reactants amounts to the stoichiometric ratio defined by the equation. 1 mol Ss 256.5 g 20.0 g Ss x 0.0780 mol S8 1 mol Cl2 88.0 g Cl2 x 1.24 mol Cl2 70.90 g 4 mol Cl2 15.9 mol Cl2 1 mol Sg 1.24 mol Cl2 0.0780 mol S8 1 mol Sg So Sg is the limiting reactant. (b What is the theoretical yield of S, Cl2 ? Theoretical yield Submit
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