How many grams of BCI3(g) [MM = 117.17 g/mol] are needed to produce 25.0 g of HCl(aq) [MM = 36.46 g/mol] in the following reaction? BCI3(g) + 3 H20() → 3 HCI(aq) + B(OH)3(aq) %3D %3D 26.8 g 80.4 g 241 g O 513 g
How many grams of BCI3(g) [MM = 117.17 g/mol] are needed to produce 25.0 g of HCl(aq) [MM = 36.46 g/mol] in the following reaction? BCI3(g) + 3 H20() → 3 HCI(aq) + B(OH)3(aq) %3D %3D 26.8 g 80.4 g 241 g O 513 g
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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QUESTION 11
How many moles of calcium chloride are needed to produce 15.7 moles of potassium chloride (assuming
excess potassium carbonate)?
CaCl2(aq) + K2CO3(aq) → 2 KCI(aq) + CaCO3(aq)
O 5.23 mol
O 7.85 mol
15.7 mol
31.4 mol
QUESTION 12
How many grams of FeCl3 [MM = 162.21 g/mol] are formed from 10.0 g of Fe203 [MM = 159.70 g/mol] and
10.0 g of HCI [MM = 36.46 g/mol] according to the following balanced equation? Which reactant is the
limiting reactant?
Fe203(s) + 6 HCI(aq) --> 2 FeCl3(aq) + 3 H20(1)
O 20.3 g; HCI
O 14.8 g; HCI
O 20.3 g; Fe203
O 14.8 g; Fe203
QUESTION 13
How many milliliters of 0.260 M Na,s are needed to react with 25.00 mL of 0.315 M AGNO3?
Na,S(ag) + 2 AgN03(aq) → 2 NaNO3(aq) + Ag25(s)
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Transcribed Image Text:* Question Completion Status:
QUESTION 11
How many moles of calcium chloride are needed to produce 15.7 moles of potassium chloride (assuming
excess potassium carbonate)?
CaCl2(aq) + K2CO3(aq) → 2 KCI(aq) + CaCO3(aq)
O 5.23 mol
O 7.85 mol
15.7 mol
31.4 mol
QUESTION 12
How many grams of FeCl3 [MM = 162.21 g/mol] are formed from 10.0 g of Fe203 [MM = 159.70 g/mol] and
10.0 g of HCI [MM = 36.46 g/mol] according to the following balanced equation? Which reactant is the
limiting reactant?
Fe203(s) + 6 HCI(aq) --> 2 FeCl3(aq) + 3 H20(1)
O 20.3 g; HCI
O 14.8 g; HCI
O 20.3 g; Fe203
O 14.8 g; Fe203
QUESTION 13
How many milliliters of 0.260 M Na,s are needed to react with 25.00 mL of 0.315 M AGNO3?
Na,S(ag) + 2 AgN03(aq) → 2 NaNO3(aq) + Ag25(s)
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25
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![v Question Completion Status:
QUESTION 9
How many grams of BCI3(g) [MM = 117.17 g/mol] are needed to produce 25.0 g of HCl(aq)
[MM = 36.46 g/mol] in the following reaction?
BCI3(g) + 3 H20() → 3 HCI(aq) + B(OH)3(aq)
26.8 g
O 80.4 g
O 241 g
O 513 g
QUESTION 10
When 10.0 g of calcium metal [MM = 40.08 g/mol] reacts with water, 5.00 g of calcium hydroxide
[MM = 74.10 g/mol] is produced. What is the percent yield for the reaction?
Ca(s) + 2 H20(1) –→ Ca(OH)2(aq) + H2g)
O 13.5%
O 27,1%
50.0%
O 92.4%
QUESTION 11
How many moles of calcium chloride are needed to produce 15.7 moles of potassium chloride (assuming
excess potassium carbonate)?
CaCl2(aq) + K2CO3(aq) → 2 KCI(ag) + CaCO3(aq)
O 5.23 mol
O7.85 mol
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Transcribed Image Text:v Question Completion Status:
QUESTION 9
How many grams of BCI3(g) [MM = 117.17 g/mol] are needed to produce 25.0 g of HCl(aq)
[MM = 36.46 g/mol] in the following reaction?
BCI3(g) + 3 H20() → 3 HCI(aq) + B(OH)3(aq)
26.8 g
O 80.4 g
O 241 g
O 513 g
QUESTION 10
When 10.0 g of calcium metal [MM = 40.08 g/mol] reacts with water, 5.00 g of calcium hydroxide
[MM = 74.10 g/mol] is produced. What is the percent yield for the reaction?
Ca(s) + 2 H20(1) –→ Ca(OH)2(aq) + H2g)
O 13.5%
O 27,1%
50.0%
O 92.4%
QUESTION 11
How many moles of calcium chloride are needed to produce 15.7 moles of potassium chloride (assuming
excess potassium carbonate)?
CaCl2(aq) + K2CO3(aq) → 2 KCI(ag) + CaCO3(aq)
O 5.23 mol
O7.85 mol
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