How many fields can the specified log processing function access in a log entry? Calculating average cache miss rates per entry using 64-byte blocks and no prefetching is done using the following code

How many fields can the specified log processing function access in a log entry? Calculating average cache miss rates per entry using 64-byte blocks and no prefetching is done using the following code

Systems Architecture

7th Edition

ISBN:9781305080195

Author:Stephen D. Burd

Publisher:Stephen D. Burd

Chapter6: System Integration And Performance

Section: Chapter Questions

Problem 22VE

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How many fields can the specified log processing function access in a log entry? Calculating average cache miss rates per entry using 64-byte blocks and no prefetching is done using the following code.
This function will be able to determine the fields in a log entry it needs to look at in order to do its job properly. The following line of code computes the average number of cache misses for each item in the cache when 64-byte cache blocks are used without any prefetching being performed by the program.
instruction is in the first picture cacheSim.h #include<stdlib.h>#include<stdio.h>#define DRAM_SIZE 1048576typedef struct cb_struct {unsigned char data[16]; // One cache block is 16 bytes.u_int32_t tag;u_int32_t timeStamp; /// This is used to determine what to evict. You can update the timestamp using cycles.}cacheBlock;typedef struct access {int readWrite; // 0 for read, 1 for writeu_int32_t address;u_int32_t data; // If this is a read access, value here is 0}cacheAccess;// This is our dummy DRAM. You can initialize this in anyway you want to test.unsigned char * DRAM;cacheBlock L1_cache[2][2]; // Our 2-way, 64 byte cachecacheBlock L2_cache[4][4]; // Our 4-way, 256 byte cache// Trace points to a series of cache accesses.FILE *trace;long cycles;void init_DRAM();// This function print the content of the cache in the following format for an N-way cache with M Sets// Set 0 : CB1 | CB2 | CB 3 | ... | CB N// Set 1 : CB1 | CB2 | CB 3 | ... | CB N// ...// Set M-1 : CB1 | CB2 | CB…
In the event of an unsatisfied cache request, what should happen to the block being sent to the main memory from the write buffer?
For a direct-mapped cache design with 64-bit addresses, the following bits of the address are used to access the cache: Tag Index Offset 63-13 12-4 3-0 a. What is the cache block size (in bytes)?b. What is the cache size (in bytes)?c. What is the total number of bits (including valid bit, tag bits and data array bits) to implement this cache?d. For the same block and cache sizes, you want to implement a 4-way set-associative cache, what is the number of index bit and the number of tag bits?
A 2-way set associative cache consists of four sets. Main memory contains 2K blocks of eight words each. Show the main memory address format that allows us to map addresses from main memory to cache. Be sure to include the fields as well as their sizes. Compute the hit ratio for a program that loops 6 times from locations 8 to 51 in main memory. You may leave the hit ratio in terms of a fraction. Please show details how you obtain the result.
3. The series of memory address references given as word addresses are 122, 126, 126, 126, 116, 300, 116, and 118. Assume a direct-mapped cache with eight one-word blocks that is initially empty. Label each reference in the list as a hit or miss and show the contents of the cache with figure after each reference.
How much of a log entry's data can a particular log processing function access? The following code determines the typical number of cache misses per entry while using 64-byte cache blocks and no prefetching.
Q e
A computer of 32 bits has a cache memory of 64 KB with a cache line size of 64 bytes. The cache access time is 20 ns, and the miss penalty is 120 ns. The cache is 2-way associative. a) What is the number of cache lines? b) What is the number of cache sets? c) What is the number of lines per set? d) Draw a scheme of this cache. e) Calculate the time to read a word in case of miss.
A cache is set up with a block size of 32 words. There are 64 blocks in cache and set up to be 4-way set associative. You have byte address 0x8923. Show the word address, block address, tag, and index Show each access being filled in with a note of hit or miss. You are given word address and the access are: 0xff, 0x08, 0x22, 0x00, 0x39, 0xF3, 0x07, 0xc0.
A direct-mapped cache consists of 8 blocks. A byte-addressable main memory contains 4K blocks of eight bytes each. Access time for the cache is 20 ns and the time required to fill a cache slot from main memory is 300 ns. Assume a request is always started in sequential to cache and then to main memory. If a block is missing from cache, the entire block is brought into the cache and the access is restarted. Initially, the cache is empty. c) Compute the effective access time for this program. Show me how to solve using this equation: EAT = H x AccessC + (1 – H) x AccessMM where H is the cache hit rate and AccessC and AccessMM are the access times for cache and main memory, respectively. thanks