How many different samples of size 3 (without replacement) can be taken from a finite population of size 10? 30 1,000 720 120
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A: Population of data: 9,5,10,11,8,12,7,6,9. Population size = N = 9.
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- O IV. None of these QUESTION 2 Question 11. (HEALTH IS WEALTH) A health conscious squirrel joined a gymnasium to run a treadmill in the month of April. At the end of the month, she noted the average mileages for a random sample of seven days is: x = 4.5 miles. She is worried to know how many miles should she run today so that her average mileage for 8 days becomes 5 miles. QUESTION 3 Question 8Find two simple random samples of size 5 by using a random number generator or Table 1 in Appendix A. Calculate the mean of each of these new samples. List these two samples. Pick any 2 numbersWhat is the value of the finite population correction factor given a population consisting of 3, 4, 5, 6, and 7 with a sample size of 2? 0.87 0.75 0.91 0.86 OOOO
- Example 10.2 Suppose there are 8 persons from whom we have to select samples of size 3. How many samples can be selected?Question 11 Public Libraries and GenderA survey1 asked a random sample of n=2752 US adults whether they had visited a public library in the last 12 months. The results for males and females are shown in the table below. Yes No Total Females 726 697 1423 Males 505 824 1329 Total 1231 1521 2752Table 1: Have you visited a public library in the last year? 1Rainie, L., “Libraries and Learning,” www.pewinternet.org/2016/04/07/libraries-and-learning/, Pew Research Center, April 7, 2016. (a) Find p^f and p^m, the sample proportions who have visited a public library in the last 12 months, for females and males respectively. What is the difference in sample proportions p^f-p^m?Round your answers to three decimal places.p^f= p^m= p^f-p^m= (b) Find a 95% confidence interval for the difference in population proportions pf-pm.Round your answers to two decimal places.The 95% confidence interval is…The information below is from the small population of 5 students. The 10 possible SRSs of size n = 3 are: Sample #1: Abigail(10), Bobby(5), Carlos(10) Sample #2: Abigail(10), Bobby(5), DeAnna(7) Sample #3: Abigail(10), Bobby(5), Emily(9) Sample #4: Abigail(10), Carlos(10), DeAnna(7) Sample #5: Abigail(10), Carlos(10), Emily(9) Sample #6: Abigail(10), DeAnna(7), Emily(9) Sample #7: Bobby(5), Carlos(10), DeAnna(7) Sample #8: Bobby(5), Carlos(10), Emily (9) Sample #9: Bobby(5), DeAnna(7), Emily(9) Sample #10: Carlos(10), DeAnna(7), Emily(9) Name Abigail Bobby Carlos DeAnna Emily Gender Female Male Male Female Female Quiz score 10 5 10 7 9 Calculate the median quiz score for each sample and display the sampling distribution of the sample median on a dotplot. 011 000000-5 5.5 7.5 T 1.5 1.5 7.5 -2 2 6.5 7 7.5 Median quiz scores 8 9 8.5 Median quiz score 8 8.5 Median quiz score ∞∞∞0-9 2.5 3.5 Median quiz scores 2.5 3 3.5 Median quiz scores -80 4104 8.5 9.5 9.5 4.5 4.5 10 8 10 ∞∞∞∞0-5 00000-5
- Three randomly selected children are surveyed. The ages of the children are 1, 4, and 10. Assume that samples of size n=2 are randomly selected with replacement from the population of 1, 4, and 10. Listed below are the nine different samples. Complete parts (a) through (4). 1.1 1,4 1,10 4,1 4,4 4,10 10,1 10.4 10,10 o a. Find the value of the population median. (Type an integer or a decimal. Do not round.)1- 6. A coach is interested in how many slam dunks the average college freshmen athis university can do. Ten volunteers from the senior class step forward. After observing their performance, the coach concludes that college seniors can do an average of 10 slam dunks in a row without missing What is the sample? What is the population?Suppose you rolled a fair six-sided die a few times and recorded the results. (You would have a collection of numbers 1-6.) Now, suppose you wanted to average these numbers. What value would you expect? If the die was rolled 6 times and the results were: 1, 4, 2, 2, 3, 2, then the average of this sample of rolls would be 2.333. This experiment could be peformed again: 6, 5, 2, 1, 1, 4. Now, the average of this sample is 3.167. Obviously, these small samples have a lot of variation in them; however, is there a way to calculate the expected average? If we were to construct a very large sample, rolling this die 1 million times, what would the expected value (mean) be? Luckily, the rules of probability allows us to do this calculation without actually having to roll the die 1 million times! Below, you will find a probability table where all of the possible outcomes from the die are listed. The first column contains the possible outcomes on the die, the second column contains the…
- 6A state fisheries commission wants to estimate the number of bass caught in a given lake during a season in order to restock the lake with the appropriate number of young fish. The commission could get a fairly accurate assessment of the seasonal catch by extensive “netting sweeps" of the lake before and after a season, but this technique is much too expensive to be done routinely. Therefore, the commission samples a number of lakes and record the seasonal catch (thousands of bass per square mile of lake area) and size of lake (square miles). A simple linear regression was performed and the following R output obtained. Estimate Std. Error t value Pr(>|t|) (Intercept) 2.5463 0.4427 5.7513 0.0000 size 0.0667 0.3672 0.1818 0.8578 If a scatterplot showed a non-linear relationship between the response and explanatory variables, what should be done? O Nothing. Continue the analysis as is. Stop the analysis. Perform a natural log transformation on the response variable first. O Perform a…Given a population of N=93, starting in row 29 of the table of random numbers, and reading across the row, select a sample of n=15 a. without replacement. b. with replacement. Column Row 00000 00001 11111 11112 22222 22223 33333 33334 12345 67890 12345 67890 12345 67890 12345 67890 28 06873 21440 75593 41373 49502 17972 82578 16364 29 12478 37622 99659 31065 83613 69889 58869 29571 30 57175 55564 65411 42547 70457 03426 72937 83792 31 91616 11075 80103 07831 59309 13276 26710 73000 32 78025 73539 14621 39044 47450 03197 12787 47709 Choose the correct answer below. A. 12, 47, 83, 76, 22, 99, 65, 93, 10, 65, 83, 61, 36, 98, 89 B. 12, 47, 83, 76, 22, 65, 93, 10, 61, 36, 89, 58, 86, 92, 71 C. 47, 83, 76, 22, 99, 65, 93, 10, 65, 83, 61, 36, 98, 89, 58 D. 83, 76, 22, 99, 65, 93, 10, 65,…
