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How many calories are needed to raise 10 g of ice at -5 °C to steam at 100 °C.
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- Four liquids are described in the table below. Use the second column of the table to explain the order of their freezing points, and the third column to explain the order of their boiling points. For example, select '1' in the second column next to the liquid with the lowest freezing point. Select '2' in the second column next to the liquid with the next higher freezing point, and so on. In the third column, select '1' next to the liquid with the lowest boiling point, '2' next to the liquid with the next higher boiling point, and so on. Note: the density of water is 1.00 g/mL. solution freezing point boiling point (choose one) ↑ 6.7 g of potassium iodide (KI) dissolved in 350. mL of water (choose one) O (choose one) (choose one) ↑ 6.7 g of hydroiodic acid (HI) dissolved in 350. mL of water 6.7 g of sucrose (C₁2H22011) dissolved in 350. mL of water (choose one) (choose one) î 350. mL of pure water (choose one) ✪ (choose one) × Ś ?How many joules of energy must be removed from 152 g of water at 18.5 °C to form ice at 0 °C?Four liquids are described in the table below. Use the second column of the table to explain the order of their freezing points, and the third column to explain the order of their boiling points. For example, select '1' in the second column next to the liquid with the lowest freezing point. Select '2' in the second column next to the liquid with the next higher freezing point, and so on. In the third column, select '1' next to the liquid with the lowest boiling point, '2' next to the liquid with the next higher boiling point, and so on. Note: the density of water is 1.00 g/mL. solution 2.2 g of ethylene glycol (C₂H602) dissolved in 200. mL of water 2.2 g of sucrose (C12H22011) dissolved in 200. mL of water 2.2 g of potassium nitrate (KNO3) dissolved in 200. mL of water 200. mL of pure water freezing point (choose one) (choose one) (choose one) (choose one) X boiling point (choose one) (choose one) O (choose one) (choose one)
- Four liquids are described in the table below. Use the second column of the table to explain the order of their freezing points, and the third column to explain the order of their boiling points. For example, select '1' in the second column next to the liquid with the lowest freezing point. Select '2' in the second column next to the liquid with the next higher freezing point, and so on. In the third column, select '1' next to the liquid with the lowest boiling point, '2' next to the liquid with the next higher boiling point, and so on. Note: the density of water is 1.00 g/mL. solution 6.0 g of ethylene glycol (C₂H6O2) dissolved in 200. mL of water 6.0 g of potassium sulfate (K₂SO4) dissolved in 200. mL of water 6.0 g of sucrose (C12H22011) dissolved in 200. mL of water 200. mL of pure water freezing point ✓ (choose one) 1(lowest) 2 3 4(highest) (choose one) X boiling point (choose one) (choose one) (choose one) (choose one) ŚFour liquids are described in the table below. Use the second column of the table to explain the order of their freezing points, and the third column to explain the order of their boiling points. For example, select '1' in the second column next to the liquid with the lowest freezing point. Select '2' in the second column next to the liquid with the next higher freezing point, and so on. In the third column, select '1' next to the liquid with the lowest boiling point, '2' next to the liquid with the next higher boiling point, and so on. Note: the density of water is 1.00 g/mL. solution 2.1 g of potassium nitrate (KNO3) dissolved in 150. mL of water 2.1 g of potassium chloride (KCI) dissolved in 150. mL of water 2.1 g of hydroiodic acid (HI) dissolved in 150. mL of water 150. mL of pure water freezing point (choose one) ✓ (choose one) ✓ (choose one) (choose one) boiling point (choose one) (choose one) (choose one) (choose one) ✓Four liquids are described in the table below. Use the second column of the table to explain the order of their freezing points, and the third column to explain the order of their boiling points. For example, select '1' in the second column next to the liquid with the lowest freezing point. Select '2' in the second column next to the liquid with the next higher freezing point, and so on. In the third column, select '1' next to the liquid with the lowest boiling point, '2' next to the liquid with the next higher boiling point, and so on. Note: the density of water is 1.00 g/mL. solution freezing point (choose onel Ⓒ boiling point (choose one) > 8.1 g of sodium bromide (NaBr) dissolved in 100. mL of water 8.1 g of glycerin (CyHyO₂) dissolved in 400. mL of water (choose one) (choose one) B 8.1 g of hydrolodic acid (HI) dissolved in 400. mL of water Ichoose onel (choose one) 400. mL of pure water [choose one) (choose one)
- You pour 84 mL of 1.5 M HNO3 and 284 mL of 0.50 M KOH over 50 g ice. The solutions and the ice were both initially at 0C. How much ice melts? Assume the heat of neutralization is -57.3 kJ/mol.Calculate the enthalpy change upon converting 45g of steam at 150 C to ice at -30 C under a constant pressure of 1 atm. The specific heats of ice, liquid water, and steam are 2.03, 4.18, and 1.84 J/g-K, respectively.How many joules of energy must be removed from 177 g of water at 16.3 °C to form ice at 0 °C?
- A liquid at 15.0 °C exhibits a vapor pressure of 0.735 atm. When heated to 30.0 ° C, the vapor pressure is 0.950 atm. What is the heat of vaporization (in kJ mol–1 to two decimal places) of the liquid?Four liquids are described in the table below. Use the second column of the table to explain the order of their freezing points, and the third column to explain the order of their boiling points. For example, select '1' in the second column next to the liquid with the lowest freezing point. Select '2' in the second column next to the liquid with the next higher freezing point, and so on. In the third column, select '1' next to the liquid with the lowest boiling point, '2' next to the liquid with the next higher boiling point, and so on. Note: the density of water is 1.00 g/mL. solution freezing point boiling point 7.3 g of glycerin (C3H8O3) dissolved in 100. mL of water (choose one) (choose one) 7.3 g of glucose (C6H1206) dissolved in 100. mL of water (choose one) (choose one) 7.3 g of potassium iodide (KI) dissolved in 100. mL of water (choose one) (choose one) 100. mL of pure water (choose one) (choose one)Four liquids are described in the table below. Use the second column of the table to explain the order of their freezing points, and the third column to explain the order of their boiling points. For example, select '1' in the second column next to the liquid with the lowest freezing point. Select '2' in the second column next to the liquid with the next higher freezing point, and so on. In the third column, select '1' next to the liquid with the lowest boiling point, '2' next to the liquid with the next higher boiling point, and so on. Note: the density of water is 1.00 g/mL. solution freezing point boiling point 2.0 g of ethylene glycol (C2H602) dissolved in 300. mL of water (choose one) (choose one) 2.0 g of potassium acetate (KCH3CO2) dissolved in 300. mL of water (choose one) (choose one) 2.0 g of glucose (C6H1206) dissolved in 300. mL of water (choose one) (choose one) 300. mL of pure water (choose one) (choose one)
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