How long does it take electrons to get from a car battery to the starting motor? Assume the current is 330 A and the electrons travel through a copper wire with cross-sectional area 0.300 cm² and length 1.00 m. The number of charge carriers per unit volume is 8.49 x 10²28 m-3.

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### How Long Does it Take Electrons to Travel from a Car Battery to the Starting Motor?

To determine the time it takes for electrons to travel from a car battery to the starting motor, we need to consider the following conditions and parameters:

- **Current (I):** 330 A
- **Cross-sectional area of the copper wire (A):** 0.300 cm² (This should be converted to square meters for calculation)
- **Length of the wire (L):** 1.00 m
- **Number of charge carriers per unit volume (n):** \( 8.49 \times 10^{28} \) m⁻³

Key concepts and formulas we will use include:

#### Drift Velocity (v_d)
The drift velocity of electrons can be calculated using the formula: 
\[ v_d = \frac{I}{n \cdot A \cdot e} \]

where:
- \( I \) is the current,
- \( n \) is the number of charge carriers per unit volume,
- \( A \) is the cross-sectional area,
- \( e \) is the charge of an electron (\( 1.602 \times 10^{-19} \) C).

#### Time Taken (t)
Once we have the drift velocity, the time taken can be found by:
\[ t = \frac{L}{v_d} \]

##### Step-by-Step Solution:
1. Convert the cross-sectional area from cm² to m²:
\[ 0.300 \text{ cm}^2 = 0.300 \times 10^{-4} \text{ m}^2 = 3.00 \times 10^{-5} \text{ m}^2 \]

2. Calculate the drift velocity \( v_d \):
\[ v_d = \frac{330 \text{ A}}{ (8.49 \times 10^{28} \text{ m}^{-3})(3.00 \times 10^{-5} \text{ m}^2)(1.602 \times 10^{-19} \text{ C})} \]

3. Determine the time \( t \):
\[ t = \frac{1.00 \text{ m}}{v_d} \]

By following these calculations, you can determine the time it takes for the electrons to travel from the car battery to the starting motor. This process illustrates not only an application
Transcribed Image Text:### How Long Does it Take Electrons to Travel from a Car Battery to the Starting Motor? To determine the time it takes for electrons to travel from a car battery to the starting motor, we need to consider the following conditions and parameters: - **Current (I):** 330 A - **Cross-sectional area of the copper wire (A):** 0.300 cm² (This should be converted to square meters for calculation) - **Length of the wire (L):** 1.00 m - **Number of charge carriers per unit volume (n):** \( 8.49 \times 10^{28} \) m⁻³ Key concepts and formulas we will use include: #### Drift Velocity (v_d) The drift velocity of electrons can be calculated using the formula: \[ v_d = \frac{I}{n \cdot A \cdot e} \] where: - \( I \) is the current, - \( n \) is the number of charge carriers per unit volume, - \( A \) is the cross-sectional area, - \( e \) is the charge of an electron (\( 1.602 \times 10^{-19} \) C). #### Time Taken (t) Once we have the drift velocity, the time taken can be found by: \[ t = \frac{L}{v_d} \] ##### Step-by-Step Solution: 1. Convert the cross-sectional area from cm² to m²: \[ 0.300 \text{ cm}^2 = 0.300 \times 10^{-4} \text{ m}^2 = 3.00 \times 10^{-5} \text{ m}^2 \] 2. Calculate the drift velocity \( v_d \): \[ v_d = \frac{330 \text{ A}}{ (8.49 \times 10^{28} \text{ m}^{-3})(3.00 \times 10^{-5} \text{ m}^2)(1.602 \times 10^{-19} \text{ C})} \] 3. Determine the time \( t \): \[ t = \frac{1.00 \text{ m}}{v_d} \] By following these calculations, you can determine the time it takes for the electrons to travel from the car battery to the starting motor. This process illustrates not only an application
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