How is the total [H3O*] of a 0.050 M aqueous solution of sulfuric acid, H,S04, determined? O H2SO, is polyprotic, so ignore Ka1, and use only K22 to solve for the [H3O*] O Since it is strong acid, the total [H,O*] is equal to 0.050 M. O Make use of both K1 and K,2 and solve the quadratic formula. O First, [H,O*] = 0.050 M, then use K2 to solve for the additional [H3O*] from the second ionization %3D

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How is the total [H3O*] of a 0.050 M aqueous solution of sulfuric acid, H,SO4, determined?
O H2SO, is polyprotic, so ignore Ka1, and use only Ka2 to solve for the [H3O*]
O Since it is strong acid, the total [H3O*] is equal to 0.050 M.
O Make use of both K,1 and K2 and solve the quadratic formula.
O First, [H3O*] = 0.050 M, then use K,2 to solve for the additional [H0*] from the second ionization
Transcribed Image Text:How is the total [H3O*] of a 0.050 M aqueous solution of sulfuric acid, H,SO4, determined? O H2SO, is polyprotic, so ignore Ka1, and use only Ka2 to solve for the [H3O*] O Since it is strong acid, the total [H3O*] is equal to 0.050 M. O Make use of both K,1 and K2 and solve the quadratic formula. O First, [H3O*] = 0.050 M, then use K,2 to solve for the additional [H0*] from the second ionization
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