At 25 °C, how many dissociated OH ions are there in 1293 mL of an aqueous solution whose pH is 1.81? number of OH ions: ions

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**Question:**

At 25 °C, how many dissociated OH⁻ ions are there in 1293 mL of an aqueous solution whose pH is 1.81?

**Answer:**

*Number of OH⁻ ions:* [                ] ions

**Explanation:**

To find the number of dissociated OH⁻ ions, we can follow these steps:

1. **Determine pOH:**
   - Since pH + pOH = 14 (at 25°C), calculate pOH as follows:
     \[
     \text{pOH} = 14 - \text{pH} = 14 - 1.81 = 12.19
     \]

2. **Calculate [OH⁻] Concentration:**
   - Use the formula \([OH⁻] = 10^{-\text{pOH}}\):
     \[
     [OH⁻] = 10^{-12.19}
     \]

3. **Find Moles of OH⁻ Ions:**
   - Convert 1293 mL to liters:
     \[
     1293 \, \text{mL} = 1.293 \, \text{L}
     \]
   - Calculate moles of OH⁻:
     \[
     \text{Moles of OH⁻} = [OH⁻] \times 1.293 \, \text{L}
     \]

4. **Calculate Number of Ions:**
   - Use Avogadro's number (\(6.022 \times 10^{23}\) ions/mole) to find the total number of ions:
     \[
     \text{Number of OH⁻ ions} = \text{Moles of OH⁻} \times 6.022 \times 10^{23}
     \]
Transcribed Image Text:**Question:** At 25 °C, how many dissociated OH⁻ ions are there in 1293 mL of an aqueous solution whose pH is 1.81? **Answer:** *Number of OH⁻ ions:* [ ] ions **Explanation:** To find the number of dissociated OH⁻ ions, we can follow these steps: 1. **Determine pOH:** - Since pH + pOH = 14 (at 25°C), calculate pOH as follows: \[ \text{pOH} = 14 - \text{pH} = 14 - 1.81 = 12.19 \] 2. **Calculate [OH⁻] Concentration:** - Use the formula \([OH⁻] = 10^{-\text{pOH}}\): \[ [OH⁻] = 10^{-12.19} \] 3. **Find Moles of OH⁻ Ions:** - Convert 1293 mL to liters: \[ 1293 \, \text{mL} = 1.293 \, \text{L} \] - Calculate moles of OH⁻: \[ \text{Moles of OH⁻} = [OH⁻] \times 1.293 \, \text{L} \] 4. **Calculate Number of Ions:** - Use Avogadro's number (\(6.022 \times 10^{23}\) ions/mole) to find the total number of ions: \[ \text{Number of OH⁻ ions} = \text{Moles of OH⁻} \times 6.022 \times 10^{23} \]
Expert Solution
Step 1

Given : 

pH = 1.81 

Volume of solution = 1293 ml 

To find :  the number of OHions 

Strategy : 1st  we are going to calculate the concentration of hydroxide ion ( using given pH data)then we will multiply it with volume to calculate number of moles of hydroxide ions and then further we can calculate number of ions of hydroxide ion present in the solution .

 

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