How is the test statistic calculated in the Wilcoxon Signed-Ranks Test?
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A: N1 = 10 df1 = 10-1 = 9 M1 = 7.8 S1 = 1.2 N2 = 10 df2 = 9 M2 = 8.1 S2 = 1.6 t-statistics = ?
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Q: What is the interpretation of the results from the Wilcoxon Signed-Ranks Test?
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Q: What is the formula used to calculate the Wilcoxon Signed-Rank test statistic?
A: Wilcoxon Signed-Rank test Non-parametric tests include the Wilcoxon signed-rank test. It is used to…
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- which of these comparison between an ANOVA and t test is correct? A. a t test provides more flexibilty in research studies than an ANOVA B. An ANOVA examines wheater mean differences exists between conditions wheres t test does not C. An ANOVA can be used to compare three or more conditions wheres a t test cannot D. A t test can be used to compare two conditions wheres an ANOVA cannot.When should the Wilcoxon Signed-Ranks Test be used instead of the paired t-test?A physical therapist wanted to know whether the mean step pulse of men was less than the mean step pulse of women. She randomly selected 54 men and 70 women to participate in the study. Each subject was required to step up and down a 6-inch platform. The pulse of each subject was then recorded. The following results were obtained. Two sample T for Men vs Women N Mean StDev SE Mean Men Women 98% CI for mu Men - mu Women (- 12.20, - 1.00) T-Test mu Men = mu Women (vs H2 O C. Ho: H1 = H2; Ha: H1 #H2 (b) Identify the P-value and state the researcher's conclusion if the level of significance was a = 0.01. What is the P-value? P-value =
- A study of parental empathy for sensitivity cues and baby temperament (higher scores mean more empathy) was performed. Let x1 be a random variable that represents the score of a mother on an empathy test (as regards her baby). Let x2 be the empathy score of a father. A random sample of 30 mothers gave a sample mean of x, = 67.85. Another random sample of 25 fathers gave x2 = 61.72. Assume that o, = 10.85 and oz = 10.57. (a) Let µ̟ be the population mean of x, and let uz be the population mean of x2. Find a 90% confidence interval for H1 - H2. (Use 2 decimal places.) lower limit upper limitthis FI 2 Z K @ In a study of treatments for very painful "cluster" headaches, 150 patients were treated with oxygen and 141 other patients were given a placebo consisting of ordinary air. Among the 150 patients in the oxygen treatment group, 107 were free from headaches 15 minutes after treatment. Among the 141 patients given the placebo, 28 were free from headaches 15 minutes after treatment. Use a 0.05 significance level to test the claim that the oxygen treatment is effective. Complete parts (a) through (c) below. 2 a. Test the claim using a hypothesis test. Consider the first sample to be the sample of patients treated with oxygen and the second sample to be the sample of patients given a placebo. What are the null and alternative hypotheses for the hypothesis test? OA. Ho: P₁ P₂ H₁: P₁ P₂ View an example F2 W S D. Ho: P1 P2 H₁: P₁ P₂ Identify the test statistic. z = 8.80 (Round to wo decin places as eeded.) Identify the P-value. P-value= (Round to three decimal places as needed.)…The local Hannaford was tracking the proportion of customers who bought flour in their stores. In mid-March they found that 65% of customers were buying flour when it was available. They want to know if that percentage has decreased now that flour is more readily available. Their hypotheses are: Ho: ρ ≥ .65 and Ha: ρ < .65. They sample 200 customers and found that 120 of them bought flour. What is the computed test statistic? Calculate the z or t, whichever is appropriate, and give the result rounded to 2 decimal places. If it's a negative number, put the negative sign before the number with no spaces between it and the number.
- The manager of a political party wants to find out the association between the campaign spending (Large, medium and small) and the vote obtained (Majority, Average and minority). Use Chi-squared hypothesis test for association to test that there is an association between the variable in campaign spending and the variable in vote obtained with five percent level of significance. The manager uses MS excel to calculate the Chi-squared stat value and the result is 8.874. Critical value: At 1% = 13.277 :At 5% = 9.488 :At 10% = 7.779 1. State the decision rule 2. Conclusion and decision 3. State the alternative hypothesis and the null hypothesisStudies show that the level of anxiety has increased since the pandemic. The average score before the pandemic was mu equal to 10. A sample of 76 individuals surveyed in the past three months produced M=12.8 and s=6.7. Based on the sample, was there a significant increase in the average anxiety level since the pandemic started at the 5% significance level? What hypothesis test is this? (a)Chi-Square Test for Independence (b)One-Sample T-Test for Mean (c)One-Sample Z-Test for Mean (d)Two-Sample T-Test for MeanA study of parental empathy for sensitivity cues and baby temperament (higher scores mean more empathy) was performed. Let x, be a random variable that represents the score of a mother on an empathy test (as regards her baby). Let x, be the empathy = 68.36. Another random sample of 31 fathers gave score of a father. A random sample of 37 mothers gave a sample mean of x, X, = 60.06. Assume that o, = 11.55 and o, = 11.45. (a) Let u, be the population mean of x, and let u, be the population mean of x,. Find a 99% confidence interval for u, - Hz. (Round your answers to two decimal places.) lower limit upper limit (b) Examine the confidence interval and explain what it means in the context of this problem. Does the confidence interval contain all positive, all negative, or both positive and negative numbers? What does this tell you about the relationship between average empathy scores for mothers compared with those for fathers at the 99% confidence level? Because the interval contains only…
- To investigate if online tutoring is as effective (measured by passing rate) as tutoring in person, we collected random samples of students using each of the tutoring method exclusively and performed two statistical analysis (Chi square and correlation). In the outputs, tutor=1 means online, tutor=0 in person, pass =1 means passed a course while 0 means failed. Choose the correct method and report your findings. Output1 Pearson Correlation Coefficients, Prob > |r| under H0: Rho=0 tutoring pass tutoring 1.00000 0.47579 0.0642 pass 0.47579 1.00000 0.0642 Output2 pass tutor Frequency‚…Which two fields of the ANOVA summary table help us find the critical value? Select all that apply A.df between B.MS within C.df within D. MS betweenThe local Hannaford was tracking the proportion of customers who bought flour in their stores. In mid-March they found that 65% of customers were buying flour when it was available. They want to know if that percentage has decreased now that flour is more readily available. Their hypotheses are: Ho: p 2 .65 and Ha: p < .65. They sample 200 customers and found that 120 of them bought flour. What is the computed test statistic? Calculate the z or t, whichever is appropriate, and give the result rounded to 2 decimal places. If it's a negative number, put the negative sign before the number with no spaces between it and the number.
