How is gaseous diffusion of uranium hexafluoride done?
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How is gaseous diffusion of uranium hexafluoride done?
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- True/False The particle transport loss due to diffusion in a circular tube is dependent on tube diameter and particle diffusivity.A Geiger-Muller tube is a type of gas-filled radiation detector. It can detect particles like X-rays, alpha particles, and beta rays (electrons). This is useful in quantizing the activity of a radioactive source or determining if an area containing radioactive material is safe to enter. If a Geiger counter is filled with 1 mol of argon gas at pressure P = 1.0620 × 10ª Pa and temperature T = 20.0 °C, what is the density p of the gas in this Geiger tube in grams per cubic centimeter? The atomic mass of argon is aa, = 39.948 g/mol. g/cm3A local shop is maintained at 101.3 kPa and 19oC. The air inside the shop is forced to leave at a rate of 150 m3/h as a result of outdoor air at 8oC infiltrating into the shop through the cracks. Determine the rate of net energy loss of the shop due to mass transfer. The gas constant of air is R = 0.287 kPa•m3/kg•K.
- A local shop is maintained at 101.3 kPa and 19oC. The air inside the shop is forced to leave at a rate of 150 m3/h as a result of outdoor air at 8oC infiltrating into the shop through the cracks. Determine the rate of net energy loss of the shop due to mass transfer. The gas constant of air is R = 0.287 kPa•m3/kg•K.A process that takes place under constant temperature and pressure is spontaneous if AG > 0. True FalseA car tire contains 0.034m^3 of air at a gauge pressure of 2.76x10^5 N/m^2. The composition of air is about 78% nitrogen (N2) and 21% oxygen (O2), both diatomic molecules. How much more internal energy, in joules, does the air in the tire have than the same volume of air has at zero gauge pressure outside the tire? Eint,2 - Eint,1 = _____
- two parts to a questionConsider a system with 1000 particles that can only have two energies, ɛ, and with ɛ, > E,. The difference between these two values is Aɛ = ɛ, -& . Assume that gi = g2 = 1. Using the %3D %3D equation for the Boltzmann distribution graph the number of particles, ni and m, in states & n2, E and E, as a function of temperature for a Aɛ = 1×10-2' J and for a temperature range from 2 to 300 K. (Note: kg = 1.380x10-23 J K-!. %3D %3D (s,-s,) gLe Aɛ/ n2 or = e n,What is the ΔS° for the reaction? Given are the S°, in J K-1 mol-1, of each substance in parentheses. SiCl4 (g, 330.73) + 2 Mg (s, 32.68) → 2 MgCl2 (s, 89.62) + Si (s, 18.83) -198.02 J/K 198.02 J/K -254.96 J/K 254.96 J/K
- In a vacuum chamber designed for surface-science experiments, the pressure of residual gas is kept as low as possible so that surfaces can be kept clean. The coverage of a surface by a single monolayer requires about 10 19 atoms per m². What pressure would be needed to deposit less than one monolayer per hour from residual gas? You may assume that if a molecule hits the surface, it sticks.The combustion of fructose (C6H12O6, MW=180.16 g/mol) takes place according to the following equation: C6H12O6(s)+6O2(g) -> 6CO2(g)+6H2O(liq) When 5.00 g of fructose are burned in excess oxygen in a bomb calorimeter with a heat capacity of 29.7 kJ•K^-1, the temperature of the calorimeter increases by 2.635 K. Calculate deltaH for the above reaction. Be sure to include the sign + or - of deltaH