How fast do small water droplets of 0.93 μm (93 x 108 m) diameter fall through the air under standard sea-level conditions? Assume the drops do not evaporate. Repeat the problem for standard conditions at 5000-m altitude. (a) Equate the expression for the drag force to that for the weight and solve for the velocity. What is the expression for the velocity of the drop? For sea level conditions: (b) What is the value of y? (c) What is the value of u? (d) What is the velocity of the droplet U? (a) U = 18μ 7D³ " 18μ 7D² U = И (b) y 9810 (c) u 0.00001789 (d) U-i 0.000005632 N/m³ N-s/m² m/s Part 3 (a) What is the viscosity at 5000 m? (b) What is the droplet velocity at 5000 m? (a)μ- (b) Vi N-s/m² m/s Part 4 (a) The Reynolds number needs to be determined to be certain that the correct expression for the drag was used. What is the density of air at sea level? (b) What is the Reynolds number at sea level? (c) Is the Reynolds number low enough to use the expression for drag? (a)p- (b) Re= i (c) kg/m³