A glass tube 1.60 m long and having a diameter of 2.5 cm is inserted vertically into a tank of oil (sg = 0.80) with the open end down and the close end uppermost. If the open end is submerged 1.30 m from the oil surface, determine the height from which the oil will rise from the tube. Assume barometric pressure is 100 kPa and neglect vapor pressure.

An oil with p= 900 kg/m and v= in Fig. E6.4. The pressure and elevation are known at sections 1 and 2, 10 m apart. Assuming 0.0002 m'/s flows upward through an inclined pipe as shown d=6 cm 10 m Pz= 250,000 Pa 40 P 350,000 Pa, z =0 steady laminar flow, (a) vetify that the flow is up, (b) compute h, between I and 2, and compute (c) Q. (d) V, and (e) Re. Is the flow really laminar? pgd'h 128uL 2,431, Eu 66 70 & Density of Air p = 1.205 kg/m 364 S44 o176 = 15 11 o76 +rso k Coefficient of viscosity for air u = 1.80 x 10-5 K hy = 151 355m Force of gravity = 9.807 Density of water p= 998 kg/m3 Coefficient of viscosity (water) u = 0.001 kg/(m.s) For gasoline at 20°C, from the Table p= 680 kg/m'y = pg, g =9.81

12. A pipe contains an oil of sp. gr. 0.8. A differential manometer connected at the two points A and B of pipe shows a difference in mercury level as 20 cm. Find the difference of pressure at the two points (Ans. 25113.6 Nm] 13. A U-tube differential manometer connects two pressure pipes A and B. Pipe A contains carbon tetrachloride having a specific gravity 1.594 under a pressure of 11.772 N/cm and pipe B contains oll of sp. gr. 0.8 under a pressure of 11.772 N/em. The pipe A lies 2.5 m above pipe B. Find the difference of [Ans. 31.36 cm of mercury] 14. A differential manometer is connected at the two points A and B as shown in Fig, 2.25. At B air pressure [Ans, 6.91 Nicm) pressure measured by mercury as fluid filling U-tube. is 7.848 N/cm (abs.), find the absolute pressure at A. AIR WATER OIL Sp. gr.0.8 OIL Sp. gr. 0.8 50'cm I. 30'am 100 am 50 cm MERCURY Sp. gr.13.6 WATER Fig. 2.25 Fig. 2.26

solve a,b,c and d given in the image provided.