How does this method work? Can you explain it step by step please?
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
How does this method work? Can you explain it step by step please?
![The following program produces 4 lines of output. Write each line of output below as it
would appear on the console.
public class ReferenceMystery1 {
public static void main(String[] args) {
int y = 1;
int x = 3;
int[] a = new int[4];
}
}
mystery (a, y, x);
System.out.println(x +
}
x = y = 1;
mystery(a, y, x);
System.out.println(x +
public static void mystery(int[] a, int x, int y) {
if (x < y) {
X++;
a[x] = 17;
} else {
a[y] = 17;
System.out.println(x +
}
+ Arrays.toString(a));
+
+ Arrays.toString(a));
+ + Arrays.toString(a));](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc3acae65-05d5-4940-8762-2c9a874e450a%2F9f2bbe87-889e-4509-99e6-0ad6dc2d9327%2Fg2uakne_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The following program produces 4 lines of output. Write each line of output below as it
would appear on the console.
public class ReferenceMystery1 {
public static void main(String[] args) {
int y = 1;
int x = 3;
int[] a = new int[4];
}
}
mystery (a, y, x);
System.out.println(x +
}
x = y = 1;
mystery(a, y, x);
System.out.println(x +
public static void mystery(int[] a, int x, int y) {
if (x < y) {
X++;
a[x] = 17;
} else {
a[y] = 17;
System.out.println(x +
}
+ Arrays.toString(a));
+
+ Arrays.toString(a));
+ + Arrays.toString(a));
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