How do I state the conditions of spontaneity on problem 7?

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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How do I state the conditions of spontaneity on problem 7?
4. Calculate the % difference in Ksp at room temperature in water and in 0.500M KCI,
equation 8. Based on a 10% acceptable difference, are your Ksp values in water and
in KCl the same? If they are not within 10% of each other, propose a specific error
that might have caused this significant difference in Ksp.
foon templese
0.180 6.207
= 12.9%
X100
%3D
6.2085
5. Calculate the AHsoln and ASsoln for the dissolution of solid KHP from the trendline
equation of your scatter graph. Include units. Refer to equation 4. R is the gas
constant 8.314 J mol K
Trendline =
4=-4280.9x ト13.049
AH= 4280-9x8.314T/mt"/
AS =
13.049 x 8.314J/mt'k
1000
1000
AHsoln =
35.59 K3/Mol ASsoln =
6. Calculate AG° soln (kJ/mol) at 25°C and 1 atm using equation 5
(35.59)-(298.15k)
AGニ- 67.79
AG =
7. Determine the equilibrium temperature (Teq equation 6) for the reaction studied and
state the conditions of spontaneity
AH =
-35.59
%3D
329.5 3%
3ס0.1
50.85°C
Equilibrium Teg: 3 30 K
State conditions of spontaneity: (temperature range where AG is negative)
Transcribed Image Text:4. Calculate the % difference in Ksp at room temperature in water and in 0.500M KCI, equation 8. Based on a 10% acceptable difference, are your Ksp values in water and in KCl the same? If they are not within 10% of each other, propose a specific error that might have caused this significant difference in Ksp. foon templese 0.180 6.207 = 12.9% X100 %3D 6.2085 5. Calculate the AHsoln and ASsoln for the dissolution of solid KHP from the trendline equation of your scatter graph. Include units. Refer to equation 4. R is the gas constant 8.314 J mol K Trendline = 4=-4280.9x ト13.049 AH= 4280-9x8.314T/mt"/ AS = 13.049 x 8.314J/mt'k 1000 1000 AHsoln = 35.59 K3/Mol ASsoln = 6. Calculate AG° soln (kJ/mol) at 25°C and 1 atm using equation 5 (35.59)-(298.15k) AGニ- 67.79 AG = 7. Determine the equilibrium temperature (Teq equation 6) for the reaction studied and state the conditions of spontaneity AH = -35.59 %3D 329.5 3% 3ס0.1 50.85°C Equilibrium Teg: 3 30 K State conditions of spontaneity: (temperature range where AG is negative)
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