how do I solve this using discrete math. Claim 3n2+8n-5 ≠ O(n). You prove such a claim by showing that ∀c>0, n0 ≥0 there exists n≥n0 : 3n2+8n-5>c*n. For problem, you need to determine a formula for the smallest value of n for which the statement above is true (in order to prove the claim.) Once you get formula for n in terms of those variables, plug in the following values for and c and n0. c=39, n0=3. Use formula to determine the smallest value of n for which the inequality holds. round answer to the nearest 2 decimal places
how do I solve this using discrete math. Claim 3n2+8n-5 ≠ O(n). You prove such a claim by showing that ∀c>0, n0 ≥0 there exists n≥n0 : 3n2+8n-5>c*n. For problem, you need to determine a formula for the smallest value of n for which the statement above is true (in order to prove the claim.) Once you get formula for n in terms of those variables, plug in the following values for and c and n0. c=39, n0=3. Use formula to determine the smallest value of n for which the inequality holds. round answer to the nearest 2 decimal places
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section1.2: Exponents And Radicals
Problem 92E
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how do I solve this using discrete math.
Claim 3n2+8n-5 ≠ O(n). You prove such a claim by showing that ∀c>0, n0 ≥0 there exists n≥n0 : 3n2+8n-5>c*n. For problem, you need to determine a formula for the smallest value of n for which the statement above is true (in order to prove the claim.) Once you get formula for n in terms of those variables, plug in the following values for
and c and n0. c=39, n0=3. Use formula to determine the smallest value of n for which the inequality holds. round answer to the nearest 2 decimal places
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