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You should have observed that the general pattern using the fractional format is: 2n 8642 I(n) = 2 2n+1 9 7 5 23 5.1 Use this fractional pattern to show that: 22n+1 (n!)² I(n) = (2n+1)! . Recall that n! = n (n-1) (n-2)-4.3.2.1 4 • 60 00100 4 6 8 Hint: Multiply the fractional pattern by the newly formed expression to its final form. 2n 2n and modify

You should have observed that the general pattern using the fractional format is: 2n 8642 I(n) = 2 2n+1 9 7 5 23 5.1 Use this fractional pattern to show that: 22n+1 (n!)² I(n) = (2n+1)! . Recall that n! = n (n-1) (n-2)-4.3.2.1 4 • 60 00100 4 6 8 Hint: Multiply the fractional pattern by the newly formed expression to its final form. 2n 2n and modify

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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You should have observed that the general pattern using the fractional format is: 2n 8642 I(n) = 2 2n+1 975 23 5.1 Use this fractional pattern to show that: 22n+1 (n!)² I(n) = (2n+1)! Recall that n! = n (n-1) (n-2)...4.3.2.1 Hint: Multiply the fractional pattern by 44 . 60 8 2n and modify 00100 4 6 8 the newly formed expression to its final form. 2n
Transcribed Image Text:You should have observed that the general pattern using the fractional format is: 2n 8642 I(n) = 2 2n+1 975 23 5.1 Use this fractional pattern to show that: 22n+1 (n!)² I(n) = (2n+1)! Recall that n! = n (n-1) (n-2)...4.3.2.1 Hint: Multiply the fractional pattern by 44 . 60 8 2n and modify 00100 4 6 8 the newly formed expression to its final form. 2n
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