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an = n! To obtain an+1, replace n by n + 1 in the formula. (n+1) n+1 (n+1)! an+1 Thus, for n ≥ 1 an+1 an (n+1) "+1 (n+1)! (n+1)" n" = (¹ + )" n As (¹ + 2)" > 1 strictly increasing. n! 72 n' this shows that the sequence is Therefore, the given sequence, increasing. {2} +∞ n=1, is strictly

an = n! To obtain an+1, replace n by n + 1 in the formula. (n+1) n+1 (n+1)! an+1 Thus, for n ≥ 1 an+1 an (n+1) "+1 (n+1)! (n+1)" n" = (¹ + )" n As (¹ + 2)" > 1 strictly increasing. n! 72 n' this shows that the sequence is Therefore, the given sequence, increasing. {2} +∞ n=1, is strictly

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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In the attached image, can you explain how to simplify the fraction? I am confused after the sentence “thus, for n>=1”
7:57 1 an To obtain an+1, replace n by n + 1 in the formula. (n+1) +1 an+1 = (n+1)! Thus, for n ≥ 1, (n+1) "+1 (n+1)! an+1 an Try solving a math problem by scanning it with X your phone. (n+1) " nn = (1 + ²)" - - ا.. n! n" As (1 + 1)" > 1 this shows that the sequence is " strictly increasing. n" n! No Therefore, the given sequence, n=1, is strictly increasing. Was this solution helpful? 口 Yes √x DO 8
Transcribed Image Text:7:57 1 an To obtain an+1, replace n by n + 1 in the formula. (n+1) +1 an+1 = (n+1)! Thus, for n ≥ 1, (n+1) "+1 (n+1)! an+1 an Try solving a math problem by scanning it with X your phone. (n+1) " nn = (1 + ²)" - - ا.. n! n" As (1 + 1)" > 1 this shows that the sequence is " strictly increasing. n" n! No Therefore, the given sequence, n=1, is strictly increasing. Was this solution helpful? 口 Yes √x DO 8
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