How do I use the chain rule to find the derivative of (y=(cosx+2sinx)8)? I know (cosx=1) and (sinx=0), how do I solve with 2 in front of sinx? Do I apply the (x8) to both (cosx) and (2sinx)? Thank you so much.
How do I use the chain rule to find the derivative of (y=(cosx+2sinx)8)? I know (cosx=1) and (sinx=0), how do I solve with 2 in front of sinx? Do I apply the (x8) to both (cosx) and (2sinx)? Thank you so much.
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter3: The Derivative
Section3.CR: Chapter 3 Review
Problem 59CR
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How do I use the chain rule to find the derivative of (y=(cosx+2sinx)8)?
I know (cosx=1) and (sinx=0), how do I solve with 2 in front of sinx? Do I apply the (x8) to both (cosx) and (2sinx)?
Thank you so much.
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How did you get from step 2 to the solution? I dont understand your example. Am I taking the derivative from the entire equation that is in the parantheses?
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