How did they get G= 10 and Pmin= 10 ? Exercise 17.A pulse radar operating at 10 GHz has an antenna with a gain of 28 dB, and a transmitter power of2 kW (peak power). If it is desired to detect a target with a cross section of 12 m², and the minimumdetectable signal is Pmin=-90 dBm, what is the maximum range of the radar?Ans:8114 m. Palsed vadar systemf = 10GHz5 = 12m² Phến -90dBmorR4&Radar equation Pr = Pt G² 2²0(47)³ R4PminG: 1028/102 2= 10€so R4.G= 28 dBPEYZPrPtG²²0Pr (47)³=DJ= 631- 90/10mW3x1081010PE = 2 kW=) R = 8114 m= 10-12= 0.0 3 мW2000 x (631) ² x 12 x (0.03)²(47)³x10-12or 8.1 km= 12m²

Answered: How did they get G= 10 and Pmin= 10 ?

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How did they get G= 10 and Pmin= 10 ?

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Concept explainers

Analog to Digital Converters

The analog-to-digital converter (ADC) allows circuits controlled by microprocessors, Arduinos, Raspberry Pi, and various reasonable digital circuits to be connected to the real world. In the real world, analog signals have a continuous stream of information from a variety of sources and sensors capable of measuring sound, light, temperature, or movement, in addition to the many digital systems that interact with their environment by measuring analog signals from those transducers.

Question

How did they get G= 10 and Pmin= 10 ?

Exercise 17.
A pulse radar operating at 10 GHz has an antenna with a gain of 28 dB, and a transmitter power of
2 kW (peak power). If it is desired to detect a target with a cross section of 12 m², and the minimum
detectable signal is Pmin=-90 dBm, what is the maximum range of the radar?
Ans:
8114 m.

Palsed vadar system
f = 10GHz
5 = 12m² Phến -90dBm
or
R4
&
Radar equation Pr = Pt G² 2²0
(47)³ R4
Pmin
G: 1028/10
2 2
= 10
€
so R4.
G= 28 dB
PE
YZ
Pr
Pt
G²²0
Pr (47)³
=
DJ
= 631
- 90/10
mW
3x108
1010
PE = 2 kW
=) R = 8114 m
= 10-12
= 0.0 3 м
W
2000 x (631) ² x 12 x (0.03)²
(47)³x10-12
or 8.1 km
= 12m²

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