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Find every thing on the chart and show work for each step

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Find every thing on the chart and show work for each step
US 360 Ri {5505 R₂11005 UX R37505 BRY 11052 FUY {RS= 750r
Transcribed Image Text:US 360 Ri {5505 R₂11005 UX R37505 BRY 11052 FUY {RS= 750r
Resistance R1 = 550 Q R2 = 1100 Q R3 = 7500 V R4 = 110 22 R5 = 750 Q RT=322.3535 0 Current IR1= 21.8182 mA IR2= 21.8182 mA IR3 = 48 MA IR4 = 41.8605 mA IRS= 41.8605 mA IT = 111.6786 mA Voltage VR1 = 12 V VR2 = 24 V VR3 = 36 V V VR4 = 4.6047 V VR5 = 31.3953 V VT = 36 V Vx = 36 V V Vy 31.3953 V Vz = 24 V Vxz = 12 V Vxy = 4.6047 V Power PR1 261.8184 mW PR2 523.6368 mW PR3 = 1.728 W PR4 192.755 mW PR5 = 1.3141 W PT = 4.0204 W Explanation: will assume that R4 = 110 and R5 = 750 2 based on the written computations in the diagram. In this way, I can show you the approach ho he problem. Step 1: Get the equivalent resistance of series-connected resistors. That would be resistors R1 and R2, as well as resistors R4 and R5. 212= R1 + R2 = 550 2 +1100 2 = 1650 , 45= R4+ R5= 110 2+ 750 = 860 N Cep 2: Simplify the circuit using the equivalent resistances.
Transcribed Image Text:Resistance R1 = 550 Q R2 = 1100 Q R3 = 7500 V R4 = 110 22 R5 = 750 Q RT=322.3535 0 Current IR1= 21.8182 mA IR2= 21.8182 mA IR3 = 48 MA IR4 = 41.8605 mA IRS= 41.8605 mA IT = 111.6786 mA Voltage VR1 = 12 V VR2 = 24 V VR3 = 36 V V VR4 = 4.6047 V VR5 = 31.3953 V VT = 36 V Vx = 36 V V Vy 31.3953 V Vz = 24 V Vxz = 12 V Vxy = 4.6047 V Power PR1 261.8184 mW PR2 523.6368 mW PR3 = 1.728 W PR4 192.755 mW PR5 = 1.3141 W PT = 4.0204 W Explanation: will assume that R4 = 110 and R5 = 750 2 based on the written computations in the diagram. In this way, I can show you the approach ho he problem. Step 1: Get the equivalent resistance of series-connected resistors. That would be resistors R1 and R2, as well as resistors R4 and R5. 212= R1 + R2 = 550 2 +1100 2 = 1650 , 45= R4+ R5= 110 2+ 750 = 860 N Cep 2: Simplify the circuit using the equivalent resistances.
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