a.Problem 1:Host IP Address:Original Subnet MaskNew Subnet Mask:Given:Find:Number of Subnet BitsNumber of Subnets CreatedNumber of Host Bits per SubnetNumber of Hosts per SubnetNetwork Address of this SubnetIPv4 Address of First Host on this SubnetIPv4 Address of Last Host on this SubnetIPv4 Broadcast Address on this Subnet192.168.200.139255.255.255.0255.255.255.224

Solution - An step by step solution is given below : 1. The given host IP Address is…

Answered: Host IP Address: Original Subnet Mask…

Host IP Address: Original Subnet Mask New Subnet Mask: Number of Subnet Bits Number of Subnets Created Given: Find: 192.168.200.139 255.255.255.0 255.255.255.224

A+ Guide To It Technical Support

10th Edition

ISBN:9780357108291

Author:ANDREWS, Jean.

Publisher:ANDREWS, Jean.

Chapter8: Network Infrastructure And Troubleshooting

Section: Chapter Questions

Problem 8TC

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b. Problem 2: Host IP Address: Original Subnet Mask New Subnet Mask: Given: Find: Number of Subnet Bits Number of Subnets Created Number of Host Bits per Subnet Number of Hosts per Subnet Network Address of this Subnet IPv4 Address of First Host on this Subnet IPv4 Address of Last Host on this Subnet IPv4 Broadcast Address on this Subnet 10.101.99.228 255.0.0.0 255.255.128.0
19. ARP is used for: O packet path determination O finding of a mapping IPV6 → MAC address O finding of a mapping IPV4 → MAC address O finding of a mapping IPV4 → TCP address
can any one please answer this question with full explanation. i found the answer but that was not well explained
1. What is the difference between packet fragmentation (i.e., at network layer) and frame frag- mentation (i.e., at link layer) in terms of purpose? 2. Suppose that host A is connected to a router R1, R1 is connected to another router, R2, and R2 is connected to host B. Suppose that a TCP message that contains 800 bytes of data and 20 bytes of TCP header is passed to the IP function at host A for delivery to B. Show the Total length, DF, MF, and Fragment offset fields of the IP header in each packet transmitted over the three links. (Assume that link A-R1 can support a maximum frame size of 1024 bytes including a 14-byte frame header, link R1-R2 can support a maximum frame size of 512 bytes, including an 8-byte frame header, and link R2-B can support a maximum frame size of 432 bytes including a 12-byte frame header.) (*hint: the Fragment offset field is denominated by 8-bytes, not bytes) 3. What is the purpose of the path MTU discovery process (see textbook Figure 5-42) and why does…
Convert IPV4, Combine Prefix, Apply Subnet, Rewrite new address: Original IPV4 Network Subnet Combined Converted Prefix ID Prefix/Subnet (48 bits) (16) The first valid address in the second 2001:FEFE:8001 1 2001:FEFE:8001:0001 subnet using 172.31.0.0/26 * The LAST valid address in the first subnet using 172.16.10.0/27 * 3000:1235:F100 16 2FOA:4444:0100 156.100.10.0 187.112.0.1 32 20
2. As a newly hired network engineer, you are tasked to compute for addresses of a newly developed network. Use 129.152.224.0/22 to compute for the subnets using VLSM method. Fill up the information in this table Required Number of Bits Borrowed Number of Host 100 Department A Department B 60 Department C 10 Department D 4 Department E 12 Department F 30 Department G Department H 10 Department I 8 Department J Department K 55 15 25 New Subnet Mask Prefix Subnetwork Number of Host Created Waste
How to solve with step by step please
4. Consider a datagram network using 8-bit host addresses. Suppose a router uses longest prefix matching and has the following forwarding table: Prefix Match Interface 10 010 1 0110 2 0111 3 11 4 00 For each of the six interfaces, give the associated range of destination host addresses and the number of addresses in the range.
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In IPV4, consider sending a 4,000 byte datagram (20 bytes of IP header) into a link that has an MTU of 1,500 bytes. The datagram will be allocated to fragments, and the offset value of the third segment is 3, 370 3, 185 4, 185 4, 370
Host A and B are communicating over a TCP connection. Host B has already received from Host A all bytes up through byte 23. Suppose Host A then sends two segments to Host B back-to-back. The first and the second segments contain 30 and 50 bytes of data, respectively. In the first segment, the sequence number is 24, the source port number is 3000, and the destination port number is 80. Host B sends an acknowledgment whenever it receives a segment from Host A. A. In the second segment sent from Host A to B, what arethe sequence number_________,source port number __________,and destination port number__________?B. If the second segment arrives after the first segment, in the acknowledgment of the second segment, what arethe acknowledgment number___________,the source port number__________,and the destination port number __________?C. If the second segment arrives before the first segment, in the acknowledgment of the first arriving segment,what is the acknowledgment number ___________?D.…
(a) There are total such subnet can have number of /17 subnets from a /11 service provider. Each of _number of hosts. (b) A network mask for an IP address in a 19 subnet has a binary representation which corresponds to an integer representation (e.g., a.b.c.d) (c) matched with _(source or destination – choose one) IP address from an IP packet is being _in a forwarding table at a router to forward packet to the next hop. (d) A distance vector routing algorithm assumes that each node know or knows – choose one) a complete network topology but (knows or does not know - choose one) (does not link cost to its neighbors. (e) An ARP Table is updated when a new node sends a frame with (what?). address to (what?). _nodes in a subnet.