horizontally from one conveyor to the next using a ramp for which uk = 0.15. The top conveyor is moving at 6 ft/s and the packages are spaced 3 ft apart. Determine the required speed of the bottom conveyor so no sliding occurs when the packages come horizontally in contact with it. What is the spacing s between the packages on the bottom conveyor?
horizontally from one conveyor to the next using a ramp for which uk = 0.15. The top conveyor is moving at 6 ft/s and the packages are spaced 3 ft apart. Determine the required speed of the bottom conveyor so no sliding occurs when the packages come horizontally in contact with it. What is the spacing s between the packages on the bottom conveyor?
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
![*14-20. Packages having a weight of 15 lb are transferred
horizontally from one conveyor to the next using a ramp for
which µk = 0.15. The top conveyor is moving at 6 ft/s and
the packages are spaced 3 ft apart. Determine the required
speed of the bottom conveyor so no sliding occurs when the
packages come horizontally in contact with it. What is the
spacing s between the packages on the bottom conveyor?
3 ft
6 ft/s
7 ft
-24 ft-
Prob. 14–20](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2411c612-2987-4ddc-becd-781e6ed4db95%2F8b4cf141-1a3c-495b-8c53-364b7253b064%2F2fduz69_processed.png&w=3840&q=75)
Transcribed Image Text:*14-20. Packages having a weight of 15 lb are transferred
horizontally from one conveyor to the next using a ramp for
which µk = 0.15. The top conveyor is moving at 6 ft/s and
the packages are spaced 3 ft apart. Determine the required
speed of the bottom conveyor so no sliding occurs when the
packages come horizontally in contact with it. What is the
spacing s between the packages on the bottom conveyor?
3 ft
6 ft/s
7 ft
-24 ft-
Prob. 14–20
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In the work-energy theorem equation, may I ask why the gravitational potential energy (mgh) is no longer included in the equation? I have noticed that only the horizontal component of the weight was included. (Wsin(theta) * inclined distance)
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