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Horizontal beam AB is supported by pin A and cable BC as shown. Pin A is in double shear and has diameter d = 15 mm. Cable BC has diameter dBc = 7.5 mm. Determine the yield safety factors of cable BC against tensile stress (SFBC) and pin A against shear stress (SFA). Both the pin and the cable are made out of 1045HR steel. Assume the shear strength of 1045HR steel is 50% of its tensile yield strength. Take 0 = 30°, L= 3 m, F = 1050 N, and go = 750 N/m.

Horizontal beam AB is supported by pin A and cable BC as shown. Pin A is in double shear and has diameter d = 15 mm. Cable BC has diameter dBc = 7.5 mm. Determine the yield safety factors of cable BC against tensile stress (SFBC) and pin A against shear stress (SFA). Both the pin and the cable are made out of 1045HR steel. Assume the shear strength of 1045HR steel is 50% of its tensile yield strength. Take 0 = 30°, L= 3 m, F = 1050 N, and go = 750 N/m.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Sy=414MPa

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Horizontal beam AB is supported by pin A and cable BC as shown. Pin A is in double shear and has diameter dд = 15 mm. Cable BC has diameter dBc = 7.5 mm. Determine the yield safety factors of cable BC against tensile stress (SFBC) and pin A against shear stress (SFA). Both the pin and the cable are made out of 1045 HR steel. Assume the shear strength of 1045HR steel is 50% of its tensile yield strength. Take 0 = 30°, L = 3 m, F = 1050 N, and q, = 750 N/m. SFBC = 6.591 SFA= = 106.045 F 7|2 ● A A C + ² —+1▬| X 0% өв X 0% qo
Transcribed Image Text:Horizontal beam AB is supported by pin A and cable BC as shown. Pin A is in double shear and has diameter dд = 15 mm. Cable BC has diameter dBc = 7.5 mm. Determine the yield safety factors of cable BC against tensile stress (SFBC) and pin A against shear stress (SFA). Both the pin and the cable are made out of 1045 HR steel. Assume the shear strength of 1045HR steel is 50% of its tensile yield strength. Take 0 = 30°, L = 3 m, F = 1050 N, and q, = 750 N/m. SFBC = 6.591 SFA= = 106.045 F 7|2 ● A A C + ² —+1▬| X 0% өв X 0% qo
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