Homework. Design a journal bearing for a centrifugal pump from the following data: Assume the diameter of the journal d as 100 mm and take 1= 150 mm ; Load on the journal = 10 000 N; Speed of the journal = 1000 r.p.m.; Type of oil is SAE 20, at 60°C; Ambient temperature of oil = 15.5°C ; Maximum bearing pressure for the pump = 1.5 N/mm. Calculate also mass of the lubricating oil required for artificial cooling, if rise of temperature of oil be limited to 20°C. Heat dissipation coefficient = 1200 W/m?/C, Specific heat of oil (S) = 1800 J/kg/°C. d = 100 mm; l = 150, W = 10 000 N ; N = 1000 r.p.m. ; to = 55°C ; Z = 0.020 kg/m-s ; ta W/m?/C; S = 1800 J/kg/°C 15.5°C ; p = 1.5 N/mm ; t = 20°C ; C = 1200

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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Homework. Design a journal bearing for a centrifugal pump from the
following data: Assume the diameter of the journal d as 100 mm and take
1 = 150 mm ; Load on the journal = 10 000 N; Speed of the journal = 1000
r.p.m.; Type of oil is SAE 20, at 60°C; Ambient temperature of oil =
15.5°C ; Maximum bearing pressure for the pump = 1.5 N/mm². Calculate
also mass of the lubricating oil required for artificial cooling, if rise of
temperature of oil be limited to 20°C. Heat dissipation coefficient = 1200
W/m?/C, Specific heat of oil (S) = 1800 J/kg/°C.
d = 100 mm; l = 150, W = 10 000 N ; N = 1000 r.p.m. ; to = 55°C ; Z =
0.020 kg/m-s ; ta
W/m?/C; S= 1800 J/kg/°C
%3D
15.5°C ; p
1.5 N/mm? ; t = 20°C ; C = 1200
Transcribed Image Text:Homework. Design a journal bearing for a centrifugal pump from the following data: Assume the diameter of the journal d as 100 mm and take 1 = 150 mm ; Load on the journal = 10 000 N; Speed of the journal = 1000 r.p.m.; Type of oil is SAE 20, at 60°C; Ambient temperature of oil = 15.5°C ; Maximum bearing pressure for the pump = 1.5 N/mm². Calculate also mass of the lubricating oil required for artificial cooling, if rise of temperature of oil be limited to 20°C. Heat dissipation coefficient = 1200 W/m?/C, Specific heat of oil (S) = 1800 J/kg/°C. d = 100 mm; l = 150, W = 10 000 N ; N = 1000 r.p.m. ; to = 55°C ; Z = 0.020 kg/m-s ; ta W/m?/C; S= 1800 J/kg/°C %3D 15.5°C ; p 1.5 N/mm? ; t = 20°C ; C = 1200
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