Homework: Find the molarity of solution of HCl that has a density of 1.19 gimiL and contains 37.0 (w/w %). How much volume is needed to prepare 100ml of 6.0M HCI from concentrated solution?
Homework: Find the molarity of solution of HCl that has a density of 1.19 gimiL and contains 37.0 (w/w %). How much volume is needed to prepare 100ml of 6.0M HCI from concentrated solution?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Solution
Us first calculate the mass of acid per liter of concentrated solution
g HNO,
L reagent
1.42 kg reagent
10
geeagent
70.5 gHNO, 1001 gHNG
100 g reagent
L reagent
kg reagent
Lieaggnt
Then,
1001 g HNO;
1 mol HNO,
15.9 mol HNO,
CHINO,
16 M
L reagent
63.0 g HNO,
L.
reagent
Homework: Find the molarity of solution of HCl that has a density of 1.19 giml
and contains 37.0 (w/w %). How much volume is needed to prepare 100mlL of
6.0M HCI from concentrated solution?
upressed as Parts per million (ppm) and parts per billion
oms of total
Parts per million (ppm) and parts per billion (ppb)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F16742ae4-cf56-4c5d-a349-470425438130%2F2510ea68-b19d-4039-81aa-40bb90917f10%2Fkch8z68_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Solution
Us first calculate the mass of acid per liter of concentrated solution
g HNO,
L reagent
1.42 kg reagent
10
geeagent
70.5 gHNO, 1001 gHNG
100 g reagent
L reagent
kg reagent
Lieaggnt
Then,
1001 g HNO;
1 mol HNO,
15.9 mol HNO,
CHINO,
16 M
L reagent
63.0 g HNO,
L.
reagent
Homework: Find the molarity of solution of HCl that has a density of 1.19 giml
and contains 37.0 (w/w %). How much volume is needed to prepare 100mlL of
6.0M HCI from concentrated solution?
upressed as Parts per million (ppm) and parts per billion
oms of total
Parts per million (ppm) and parts per billion (ppb)
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