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Determine the molarity and mole fraction of a 1.01 m solution of acetone (CH3COCH3) dissolved in ethanol (C₂H5OH). (Density of acetone = 0.788 g/cm³; density of ethanol = 0.789 g/cm³.) Assume that the final volume equals the sum of the volumes of acetone and ethanol. ✓ mol/L X molarity 0.753 mole fraction 0.956

Determine the molarity and mole fraction of a 1.01 m solution of acetone (CH3COCH3) dissolved in ethanol (C₂H5OH). (Density of acetone = 0.788 g/cm³; density of ethanol = 0.789 g/cm³.) Assume that the final volume equals the sum of the volumes of acetone and ethanol. ✓ mol/L X molarity 0.753 mole fraction 0.956

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter13: Solutions And Their Behavior
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Determine the molarity and mole fraction of a 1.01 m solution of acetone (CH3COCH3) dissolved in ethanol (C₂H5OH). (Density of acetone = 0.788 g/cm³; density of ethanol that the final volume equals the sum of the volumes of acetone and ethanol. molarity 0.753 mol/L mole fraction 0.956 = 0.789 g/cm³.) Assume
Transcribed Image Text:Determine the molarity and mole fraction of a 1.01 m solution of acetone (CH3COCH3) dissolved in ethanol (C₂H5OH). (Density of acetone = 0.788 g/cm³; density of ethanol that the final volume equals the sum of the volumes of acetone and ethanol. molarity 0.753 mol/L mole fraction 0.956 = 0.789 g/cm³.) Assume
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