Home Work:1. Draw shear force and bending moment diagrams for the beam shown in figure.30kN2m10KN/m10m2. Draw shear force and bending moment diagrams for the beam shown in figure.50 kN/m20 kN/mAB2 m2 m -2 mRARo3. Relation between load, shear and moment:Please solve according tothe exporters of a typicalsolution.We will discuss the relations existing between the loads, shears and bendingmoments in any beam. Theses relations provide a method of constructing sheaand moment diagrams without writing shear and moment equations.The beam shown in figure (1) is assumed to carry any general loading.The free body diagramwdxW (N/m)wdxof segment of this beam%3Dof length (dx) is shownin figure (2).butwdx> is the summation of area between (x, and x;)RỊR:.. V, -V, = AV = (area) jnndsimilarly(1)(2)SF =0=V + wdx-(V+dV) =0dM =w ----- Intensity of load (N/m): dV = wdM, - M, = AM = (area ),herEM, =0= M +Vdx + (wdx)dx-(M + dM) =0(de)?. w 3=APWhere:zerodx(slope of shear diagram).. dM =VdxdM:V =dx(slope of moment diagram)for (dV = wdx )we can integrating

Answered: Image /qna-images/answer/c579e5e2-016c-4587-b185-783f573e2b0e.jpg

Home Work: 1. Draw shear force and bending moment diagrams for the beam shown in figure. 30kN 2m B 10KN/m 10m 2. Draw shear force and bending moment diagrams for the beam shown in figure. 50 kN/m 20 kN/m 2 m 2 m 2 m RA Ro 3. Relation between load, shear and moment: Please solve according to the exporters of a typical solution. We will discuss the relations existing between the loads, shears and be moments in any beam. Theses relations provide a method of constructing and moment diagrams without writing shear and moment equations. The beam shown in figure (1) is assumed to carry any general loading. The free body diagram wds W (N/m) :- wdx of segment of this beam of length (dx) is shown in figure (2). but wdx = is the summation of area between (x; and x;) RI R: ..V -V, = AV = (area)nd similarly (1) (2 EF, =0=V +wdx-(V +dV) =0 dM = w -------- Intensity of load (N/m) . dV =wdx M, - M, = AM = (area ),her EM, =0> M +Vdx+ (wdx) dx -(M + dM) =0 dV (de)2 Where: zero (slope of shear diagram) 2 .. dM =Vdx for (dV = wdx ) dx dM ..V = dx (slope of moment diagram) we can integrating

Home Work: 1. Draw shear force and bending moment diagrams for the beam shown in figure. 30kN 2m B 10KN/m 10m 2. Draw shear force and bending moment diagrams for the beam shown in figure. 50 kN/m 20 kN/m 2 m 2 m 2 m RA Ro 3. Relation between load, shear and moment: Please solve according to the exporters of a typical solution. We will discuss the relations existing between the loads, shears and be moments in any beam. Theses relations provide a method of constructing and moment diagrams without writing shear and moment equations. The beam shown in figure (1) is assumed to carry any general loading. The free body diagram wds W (N/m) :- wdx of segment of this beam of length (dx) is shown in figure (2). but wdx = is the summation of area between (x; and x;) RI R: ..V -V, = AV = (area)nd similarly (1) (2 EF, =0=V +wdx-(V +dV) =0 dM = w -------- Intensity of load (N/m) . dV =wdx M, - M, = AM = (area ),her EM, =0> M +Vdx+ (wdx) dx -(M + dM) =0 dV (de)2 Where: zero (slope of shear diagram) 2 .. dM =Vdx for (dV = wdx ) dx dM ..V = dx (slope of moment diagram) we can integrating

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Slope and Deflection

The slope in a deflected beam is described as an angle in radians made by the tangent of the section with the original axis of the beam. The deflection at any point on the axis of the beam is defined as the lateral displacement of the point before and after loading.

Question

Home Work:
1. Draw shear force and bending moment diagrams for the beam shown in figure.
30kN
2m
10KN/m
10m
2. Draw shear force and bending moment diagrams for the beam shown in figure.
50 kN/m
20 kN/m
A
B
2 m
2 m -
2 m
RA
Ro
3. Relation between load, shear and moment:
Please solve according to
the exporters of a typical
solution.
We will discuss the relations existing between the loads, shears and bending
moments in any beam. Theses relations provide a method of constructing shea
and moment diagrams without writing shear and moment equations.
The beam shown in figure (1) is assumed to carry any general loading.
The free body diagram
wdx
W (N/m)
wdx
of segment of this beam
%3D
of length (dx) is shown
in figure (2).
but
wdx
> is the summation of area between (x, and x;)
RỊ
R:
.. V, -V, = AV = (area) jnnd
similarly
(1)
(2)
SF =0=V + wdx-(V+dV) =0
dM =
w ----- Intensity of load (N/m)
: dV = wd
M, - M, = AM = (area ),her
EM, =0= M +Vdx + (wdx)
dx
-(M + dM) =0
(de)?
. w 3=
AP
Where:
zero
dx
(slope of shear diagram)
.. dM =Vdx
dM
:V =
dx
(slope of moment diagram)
for (dV = wdx )
we can integrating

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