HO, + CH30 CH3OH +

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Which side must be favored?

The chemical equation in the image represents an equilibrium reaction between a benzoate ion and methanol:

- On the left side of the equation:
  - The benzoate ion is shown with a benzene ring (a hexagon with alternating double bonds) attached to a carboxylate group (\( \text{COO}^{-} \)).
  - Methanol (\( \text{CH}_3\text{OH} \)) is a simple alcohol composed of a methyl group (\( \text{CH}_3 \)) attached to a hydroxyl group (\( \text{OH} \)).

- The equilibrium arrow (\( \rightleftharpoons \)) indicates that the reaction can proceed in both directions.

- On the right side of the equation:
  - Benzoic acid is formed, with the benzene ring attached to a carboxylic acid group (\( \text{COOH} \)).
  - The methoxide ion (\( \text{CH}_3\text{O}^{-} \)) is formed, which is the conjugate base of methanol.

This reaction illustrates an acid-base equilibrium where the benzoate ion acts as a base and methanol as an acid.
Transcribed Image Text:The chemical equation in the image represents an equilibrium reaction between a benzoate ion and methanol: - On the left side of the equation: - The benzoate ion is shown with a benzene ring (a hexagon with alternating double bonds) attached to a carboxylate group (\( \text{COO}^{-} \)). - Methanol (\( \text{CH}_3\text{OH} \)) is a simple alcohol composed of a methyl group (\( \text{CH}_3 \)) attached to a hydroxyl group (\( \text{OH} \)). - The equilibrium arrow (\( \rightleftharpoons \)) indicates that the reaction can proceed in both directions. - On the right side of the equation: - Benzoic acid is formed, with the benzene ring attached to a carboxylic acid group (\( \text{COOH} \)). - The methoxide ion (\( \text{CH}_3\text{O}^{-} \)) is formed, which is the conjugate base of methanol. This reaction illustrates an acid-base equilibrium where the benzoate ion acts as a base and methanol as an acid.
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